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3 years ago

What is TRUE about how the “CSI effect” has been represented in society?

1 answer:

8 0

Crime and courtroom proceedings have long been fodder for film and ... process, many of today's courtroom dramas are based on actual cases. ... acquit guilty defendants when no scientific evidence has been presented.

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Which has a higher electronegativity phosphorus or sodium

Yuliya22 [10]

Answer:

it is phosphorus it has o most 2 times as much electromagnetically

Explanation:

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3 years ago

What will happen if you take a frog out of the food chain?

Setler [38]

there are a number of animals that eat frogs that will die off, then the animals that eat them will go hungry, and their populations will die off as well. This would just keep going up the food chain. Essentially, the loss of the frogs could have deep, reverberating effects that we may not grasp until it’s too late.

4 0

4 years ago

If helium effuses through a porous barrier in 1.34 min, how much time (in min) would it take the same amount of ammonia to effus

timofeeve [1]

Answer:

The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.

Explanation:

Let the volume of the helium gas be = V

Time taken by the helium gas = t = 1.34 min

Effusion rate of helium gas = $R=\frac{V}{1.34 min}$

If V volume of ammonia effuse through same porous barrier the effusion rate of ammonia gas will be given as:

$R'=\frac{V}{t'}$

Using Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

Molar mass of helium gas = M = 4 g/mol

Molar mass of ammonia gas = M' = 17 g/mol

$\frac{R}{R'}=\sqrt{\frac{M'}{M}}$

$\frac{\frac{V}{1.34 min}}{\frac{V}{t'}}=\sqrt{\frac{17 g/mol}{4 g/mol}}$

$t'=1.34 min\times \sqrt{\frac{17 g/mol}{4 g/mol}}=2.76 min$

The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.

8 0

3 years ago

How many moles of N20 gas would have a volume of 3.8 L at 460 mmHg and 77°C?

Citrus2011 [14]

We are given:

Volume of gas = 3.8 L

Pressure = 460 mmHg

Temperature = 77°c = (77+273)K = 350K

Converting the pressure to atm:

Pressure(in atm) = Pressure(in mmHg) / 760

Pressure = 460/760 = 0.6 atm

Finding the number of moles:

using the ideal gas equation:

PV = nRT [where R is the universal gas constant]

replacing the given values in this equation

(0.6)(3.8) = n(0.082)(350)

n = (0.6*3.8)/(0.082*350)

n = 0.08 moles

7 0

3 years ago

A container is filled with 12.5 g of O, gas, what is this amount in liters?

g100num [7]

12.5 gallons is 47.3 liters

hope that helps

6 0

3 years ago