here is some facts
Limestone is a sedimentary rock, whereas marble is metamorphic. These two rock types can be distinguished by their textures. ... 2- Gabbro and basalt are two igneous rocks having the same chemical composition, and the same minerals (plagioclase feldspar + pyroxene), but are of different origins.
The molarity of a solution prepared by dissolving 141.6g of citric acid in water is calculated as below
find the the number of moles
moles= mass/molar mass
= 141.6 g/ 192 g/mol = 0.738 moles
molarity= moles/molar mass
= 0.738/3500 x1000 = 0.21 M
This is an incomplete question, here is a complete question.
The Henry's law constant for oxygen dissolved in water is 4.34 × 10⁹ g/L.Pa at 25⁰C.If the partial pressure of oxygen in air is 0.2 atm, under atmospheric conditions, calculate the molar concentration of oxygen in air-saturated and oxygen saturated water.
Answer : The molar concentration of oxygen is, 
Explanation :
As we know that,

where,
= molar solubility of
= ?
= partial pressure of
= 0.2 atm = 1.97×10⁻⁶ Pa
= Henry's law constant = 4.34 × 10⁹ g/L.Pa
Now put all the given values in the above formula, we get:


Now we have to molar concentration of oxygen.
Molar concentration of oxygen = 
Therefore, the molar concentration of oxygen is, 
Answer:
<h2>The answer is 0.07 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula

From the question
mass = 31 g
density = 444 g/mL
We have

We have the final answer as
<h3>0.07 mL</h3>
Hope this helps you