Answer:
The vapor-pressure lowering of the solution is 2,39 mmHg
Explanation:
The Raoult's law says that the vapor pressure of a solvent in a solution is always lower than the vapor pressure of the pure solvent. The vapor pressure lowering is directly proportional to the mole fraction of the solute. In mathematical terms that means:
ΔP =
<em>(1)</em>
Where:
ΔP is the vapor-pressure lowering of the solution
is molar fraction of solute
And
is the capor pressure of the pure solvent (86,0 mmHg)
The moles of naphthalene are:
<em>9,36x10⁻³ moles solute</em>
And the moles of benzene are:
0,328 moles solvent
Molar fraction of solute is:
<em>0,0278</em>
Replacing in (1)
<em>ΔP = 2,39 mm Hg</em>
I hope it helps!
hey sorry I need a free point !
Answer: The volume of the gas in the squirrel now is 0.00532 L
Explanation:
To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
![\frac{V_1}{T_1}=\frac{V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7BT_1%7D%3D%5Cfrac%7BV_2%7D%7BT_2%7D)
where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
![V_1=0.005L\\T_1=308K\\V_2=?\\T_2=328K](https://tex.z-dn.net/?f=V_1%3D0.005L%5C%5CT_1%3D308K%5C%5CV_2%3D%3F%5C%5CT_2%3D328K)
Putting values in above equation, we get:
![\frac{0.005}{308}=\frac{V_2}{328}\\\\V_2=0.0053L](https://tex.z-dn.net/?f=%5Cfrac%7B0.005%7D%7B308%7D%3D%5Cfrac%7BV_2%7D%7B328%7D%5C%5C%5C%5CV_2%3D0.0053L)
Thus the volume of the gas in the squirrel now is 0.00532 L