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3 years ago

What happens when you combine ammonia and formaldehyde?

Chemistry

1 answer:

bija089 [108]3 years ago

5 0

Answer:

The mechanism for the formation of hexamethylenetetraamine predicts the formation of aminomethanol from the addition of ammonia to formaldehyde. This molecule subsequently undergoes unimolecular decomposition to form methanimine and water.

Explanation:

Brainliest please?

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Aldehydes may oxidize to form:

Arlecino [84]

Aldehydes may oxidize to form carboxylic acid <span>exception to oxidizing formaldehyde with strong oxidizing agent.

HCHO + 3[O] = CO</span>₂ + H₂O

5 0

4 years ago

Read 2 more answers

A chemist designs a galvanic cell that uses these two half-reactions:

Nonamiya [84]

Answer :

(a) Reaction at anode (oxidation) : $4Fe^{2+}\rightarrow 4Fe^{3+}+4e^-$

(b) Reaction at cathode (reduction) : $O_2+4H^++4e^-\rightarrow 2H_2O$

(c) $O_2+4H^++4Fe^{2+}\rightarrow 2H_2O+4Fe^{3+}$

(d) Yes, we have have enough information to calculate the cell voltage under standard conditions.

Explanation :

The half reaction will be:

Reaction at anode (oxidation) : $Fe^{2+}\rightarrow Fe^{3+}+e^-$ $E^0_{anode}=+0.771V$

Reaction at cathode (reduction) : $O_2+4H^++4e^-\rightarrow 2H_2O$ $E^0_{cathode}=+1.23V$

To balance the electrons we are multiplying oxidation reaction by 4 and then adding both the reaction, we get:

Part (a):

Reaction at anode (oxidation) : $4Fe^{2+}\rightarrow 4Fe^{3+}+4e^-$ $E^0_{anode}=+0.771V$

Part (b):

Reaction at cathode (reduction) : $O_2+4H^++4e^-\rightarrow 2H_2O$ $E^0_{cathode}=+1.23V$

Part (c):

The balanced cell reaction will be,

$O_2+4H^++4Fe^{2+}\rightarrow 2H_2O+4Fe^{3+}$

Part (d):

Now we have to calculate the standard electrode potential of the cell.

$E^o=E^o_{cathode}-E^o_{anode}$

$E^o=(1.23V)-(0.771V)=+0.459V$

For a reaction to be spontaneous, the standard electrode potential must be positive.

So, we have have enough information to calculate the cell voltage under standard conditions.

4 0

3 years ago

When we have two sorted lists of numbers in non-descending order, and we need to merge them into one sorted list, we can simply

Dovator [93]

Answer:

Explanation:

Firstly of all we have to construct the min-heap of the k-sub list and each sub list which is a node in the constructed min-heap.

We have several steps to follows:

Step-1. When we compare the two sub lists, at the starting we can compare their first elements which is actually their minimum elements.

Step-2. The min-heap formation will cost be O(k) time.

Step-3. After the step 1 & step 2 we can run the minimum algorithm which can be extracted from the minimum element in the root list.

Step-4. Then Update the root list in the heap and after that simplify the min-heap as maintained by the new minimum element in the root list.

Step-5. If any root sub-list becomes empty in the step 4 then we can take any leaf sub-list from the root and simplify it.

Step-6. At every Extraction of the element it can take up to O(log k) time.

Hence, We can say that the extract of n element in the total whose

Running time will be O(n log k + k) which can be equal to the O(n log k+ k) (since k < n).

7 0

3 years ago

The atomic number of krypton (Kr) is 36, and its mass number is 84. How many neutrons does it have?

AleksAgata [21]

i believe the answer is 48 neutrons

3 0

3 years ago

Read 2 more answers

What are you measuring when

wariber [46]

Answer:

B. the amount of atoms you contain

3 0

2 years ago