All categories

4 years ago

What’s the answer??????? Pleaseeeeeeee helppppppppppp

Mathematics

2 answers:

Vinvika [58]4 years ago

5 0

Hello from MrBillDoesMath!

Answer:

Choice A, 18x - 6y = 20

Discussion:

Given line

-9x + 3y = 12 (M)

Choice A:

18x - 6y = 20 => divide both sides by -2

-9x + 3y = -10 (N)

The left hand sides of (M) and (N) are equal implying that right hand sides are equal which further implies 12 = -10. Contradiction! so the system M and N has no solution.

Thank you,

MrB

Svetlanka [38]4 years ago

4 0

The answer is a!!!!!!!!!!

You might be interested in

A simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute

GREYUIT [131]

Answer:

(a) Null Hypothesis, $H_0$ : $\sigma$ = 10 beats per minute

Alternate Hypothesis, $H_A$ : $\sigma\neq$ 10 beats per minute

(b) The value of chi-square test statistics is 35.704.

(c) P-value = 0.4360.

(d) We conclude that the pulse rates of men have a standard deviation equal to 10 beats per minute.

Step-by-step explanation:

We are given that a simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute.

If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute.

Let $\sigma$ = population standard deviation for the pulse rates of men.

(a) So, Null Hypothesis, $H_0$ : $\sigma$ = 10 beats per minute {means that the pulse rates of men have a standard deviation equal to 10 beats per minute}

Alternate Hypothesis, $H_A$ : $\sigma\neq$ 10 beats per minute {means that the pulse rates of men have a standard deviation different from 10 beats per minute}

The test statistics that will be used here is One-sample chi-square test for standard deviation;

T.S. = $\frac{(n-1)\times s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, s = sample standard deviation = 10.1 beats per minute

n = sample of men = 36

So, the test statistics = $\frac{(36-1)\times 10.1^{2} }{10^{2} }$ ~ $\chi^{2}__3_5$

= 35.70 4

(b) The value of chi-square test statistics is 35.704.

(c) Also, the P-value of the test statistics is given by;

P-value = P( $\chi^{2}__3_5$ > 35.704) = 0.4360

(d) Since the P-value of our test statistics is more than the level of significance as 0.4360 > 0.10, so we have insufficient evidence to reject our null hypothesis as the test statistics will not fall in the rejection region.

Therefore, we conclude that the pulse rates of men have a standard deviation equal to 10 beats per minute.

3 0

4 years ago

The formula for an arithmetic series is shown below, where n = 1, 2, 3 ...

lisov135 [29]

Answer:

4th term = 28

5th term = 37

6th term = 45

Step-by-step explanation:

f(n + 1) = f(n) + 8

f(1) = 5

f(1 + 1) = f(1) + 8 = 5+8 = 13

f(2) = 13

f(2 + 1) = f(2) + 8 = 13+8 = 21

Thus, series is 5, 13, 21......

In arithmetic series

Nth term is given by

n th term = a + (n-1)d

where a is the first term

and d is the common difference.

common difference d = nth term - (n-1)th term

For this series

a = 5

lets take nth term as 2nd term and 1st term as (n-1)th term

d = 13-5 = 8

n th term = a + (n-1)d

using the formula for nth term

4th term = 5 + (4-1)8 = 29

5th term = 5 + (5-1) 8= 37

6th term = 5+ (6-1)8 = 45

Thus, 4th term = 28

5th term = 37

6th term = 45

Note this, problem can be solved using f(n + 1) = f(n) + 8 by putting n = 3,4,5 as well but for learning concept of arithmetic series, i have used above process. Hope it helps.

5 0

3 years ago

Classify the events as dependent or independent. the events of getting two aces when two cards are drawn from a deck of playing

Thepotemich [5.8K]

The events are dependent.

When the first card is not replaced, you change the probability of the second card. At the very least, you have changed the total number of cards to draw from.

6 0

4 years ago

2) Subtract and simplify. 11 7\10 − 7 3\10 =

Free_Kalibri [48]

Answer:

4 2/5

Step-by-step explanation:

11 7/10

- 7 3/10

----------------

4 4/10

4 4/10 = 4 2/5

4 0

3 years ago

Alex is feeling stressed this morning. He did not get enough sleep because a dog barked most of the night. The dog barked from 1

inna [77]

Answer:

Poor Alex, I know how they feel, I got a dog myself.

The amount of time between

11:41 pm to 12:09 am is

19 minutes (to 12 am, 60 minutes to next hour) + 9

which is 28 minutes for the first dog barking session

the second time is 35 minutes,

using same method as before.

adding the two separte barking sessions we get

35+28= 63 minutes

which is equivelant to 1 hour and 3 minutes.

In conclusion the dog barks for 1 hour and 3 minutes in total.

7 0

2 years ago