Question

A line has a slope of mc013-1.jpg and passes through the point (–5, 4). Which is the equation of the line?

Answer 1

Answer:

y = $\frac{-3x}{4}$ + $\frac{1}{4}$.

Step-by-step explanation:

Given : Graph of slope $\frac{-3}{4}$ and passes through the point (–5, 4).

To find : Which is the equation of the line.

Solution : we have given that point ( -5 ,4)

By equation of line ($y-y_{1}) = m (x -x_{1})$

y - 4 =  $\frac{-3}{4}$( x +5).

y - 4 =  $\frac{-3x}{4}$ +$\frac{-15}{4}$.

On adding 4  both sides we get,

y = $\frac{-3x}{4}$ + $\frac{-15}{4}+4$.

y = $\frac{-3x}{4}$ + $\frac{-15 +16}{4}$.

y = $\frac{-3x}{4}$ + $\frac{1}{4}$.

Therefore, y = $\frac{-3x}{4}$ + $\frac{1}{4}$.

Answer 2

Y - 4= 3/4(x + 5)

y - 4= - (3/4)x - 15/4

y - 16/4= -(3/4)x - 15/4

y= - (3/4)x + 1/4

the answer is b