A piece of lithium is placed on the surface of some water in a beaker. hydrogen is given off. Lithium hydroxide is formed. What
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The question is incomplete, here is the complete question:
When silver nitrate reacts with copper, copper(II) nitrate and silver are produced. The balanced equation for this reaction is:
Suppose 6 moles of silver nitrate react. The reaction consumes___ moles of copper. The reaction produces __ moles of copper(II) nitrate and __ moles of silver.
<u>Answer:</u> The amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.
<u>Explanation:</u>
We are given:
Moles of silver nitrate = 6 moles
For the given chemical reaction:
- <u>For copper metal:</u>
By Stoichiometry of the reaction:
2 moles of silver nitrate reacts with 1 mole of copper metal
So, 6 moles of silver nitrate will react with = of copper metal
Moles of copper reacted = 3 moles
- <u>For copper(II) nitrate:</u>
By Stoichiometry of the reaction:
2 moles of silver nitrate produces 1 mole of copper(II) nitrate
So, 6 moles of silver nitrate will produce = of copper(II) nitrate
Moles of copper(II) nitrate produced = 3 moles
- <u>For silver metal:</u>
By Stoichiometry of the reaction:
2 moles of silver nitrate produces 2 moles of silver metal
So, 6 moles of silver nitrate will produce = of silver metal
Moles of silver metal produced = 3 moles
Hence, the amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.
Answer:
See explanation below
Explanation:
The first two pictures show the reagents used in these reactions a) and b). As it was stated, An E2 reaction proceeds with an antiperiplanar stereochemistry, so in the case of reaction a) it fill form a product with the groups in opposite directions. In other words, a Trans product.
In the case of reaction b) we have the same reaction, with the difference that we have changed the CH3 and phenyl group of positions. This will cause that the reaction will proceed the same but the stereochemistry of the final product will be changed too. In this case, and according to the picture 3 attached, we can see that the product formed is a cis product. So we can conclude that the relation of product a) and b) is that they are isomers, the trans and cis isomers respectively. See picture below for mechanism and products
