What is the volume (ML) of water

What is silver?Hows it formed?Who created it?Make sure you include the year.At least 5 sentences for each.

mylen [45]

Silver is A precious shiny grayish-white metal, the chemical element of atomic number 47. Silver is sometimes found in nature in metallic form. It forms a sulfide mineral Ag 2 S called acanthite. Mineral forms of silver include sulfides formed with antimony called Stephanite, miargyrite and pyrargyrite. Silver is a naturally occurring element on the periodic table and can be found in natural deposits throughout the world. As such, it was discovered in 5000 BC, but not invented, by people.

3 0

3 years ago

Suppose you are provided with a 30.86 g sample of potassium chlorate to perform this experiment. What is the mass of oxygen you

oee [108]

Answer:

The mass of oxygen is 12.10 g.

Explanation:

The decomposition reaction of potassium chlorate is the following:

2KClO₃(s) → 2KCl(s) + 3O₂(g)

We need to find the number of moles of KClO₃:

$\eta_{KClO_{3}} = \frac{m}{M}$

Where:

m: is the mass = 30.86 g

M: is the molar mass = 122.55 g/mol

$\eta_{KClO_{3}} = \frac{30.86 g}{122.55 g/mol} = 0.252 moles$

Now, we can find the number of moles of O₂ knowing that the ratio between KClO₃ and O₂ is 2:3

$\eta_{O_{2}} = \frac{3}{2}*0.252 moles = 0.378 moles$

Finally, the mass of O₂ is:

$m = 0.378 moles*32 g/mol = 12.10 g$

Therefore, the mass of oxygen is 12.10 g.

I hope it helps you!

6 0

3 years ago

10 points!

Alik [6]

I believe that it is all of the above.

"A Scientific Hypothesis Must Be "Falsifiable". A scientific hypothesis must be testable, but there is a much stronger requirement that a testable hypothesis must meet before it can really be considered scientific."

I hope this helped, have a nice day!

6 0

3 years ago

Read 2 more answers

If the sample contained 2.0 moles of KClO3 at a temperature of 214.0 °C, determine the mass of the oxygen gas produced in grams

Westkost [7]

Answer : The mass of the oxygen gas produced in grams and the pressure exerted by the gas against the container walls is, 96 grams and 1.78 atm respectively.

Explanation : Given,

Moles of $KCl_3$ = 2.0 moles

Molar mass of $O_2$ = 32 g/mole

Now we have to calculate the moles of $MgO$

The balanced chemical reaction is,

$2KClO_3\rightarrow 2KCl+3O_2$

From the balanced reaction we conclude that

As, 2 mole of $KClO_3$ react to give 3 mole of $O_2$

So, 2.0 moles of $KClO_3$ react to give $\frac{2.0}{2}\times 3=3.0$ moles of $O_2$

Now we have to calculate the mass of $O_2$

$\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2$

$\text{ Mass of }O_2=(3.0moles)\times (32g/mole)=96g$

Therefore, the mass of oxygen gas produced is, 96 grams.

Now we have to determine the pressure exerted by the gas against the container walls.

Using ideal gas equation:

$PV=nRT\\\\PV=\frac{w}{M}RT\\\\P=\frac{w}{V}\times \frac{RT}{M}\\\\P=\rho\times \frac{RT}{M}$

where,

P = pressure of oxygen gas = ?

V = volume of oxygen gas

T = temperature of oxygen gas = $214.0^oC=273+214.0=487K$

R = gas constant = 0.0821 L.atm/mole.K

w = mass of oxygen gas

$\rho$ = density of oxygen gas = 1.429 g/L

M = molar mass of oxygen gas = 32 g/mole

Now put all the given values in the ideal gas equation, we get:

$P=1.429g/L\times \frac{(0.0821L.atm/mole.K)\times (487K)}{32g/mol}$

$P=1.78atm$

Thus, the pressure exerted by the gas against the container walls is, 1.78 atm.

7 0

3 years ago

what is the mole fraction of neon in a mixture that contains 0.628 g of helium, 11.491 g of neon, and 7.613 g of argon?

VMariaS [17]

Answer:

0.2

Explanation:

Given parameters:

Mass of helium = 0.628g

Mass of neon = 11.491g

Mass of argon = 7.613g

Unknown:

Mole fraction of neon = ?

Solution:

The mole fraction of an element is the number of moles of that element to the total number of moles in the gas mixture.

We need to calculate the number of moles of each element first;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of Helium = 4g/mol

Molar mass of Neon = 20g/mol

Molar mass of Argon = 40g/mol

Number of moles of He = $\frac{0.628}{4}$ = 0.16moles

Number of moles of Ne = $\frac{11.491}{20}$ = 0.58moles

Number of moles of Ar = $\frac{7.613}{40}$ = 0.19moles

Total number of moles = 0.16moles + 0.58moles + 0.19moles = 0.93moles

Mole fraction Neon = $\frac{0.19}{0.93}$ = 0.2

4 0

3 years ago