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polet [3.4K]
2 years ago
7

What is the volume (ML) of water

Chemistry
1 answer:
Dovator [93]2 years ago
6 0

Answer:

hello :)

One milliliter (1 mL) of water has a volume of 1 cubic centimeter (1cm3).

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satela [25.4K]

Answer:

FeSO2

Explanation:

Please see attached picture for full solution.

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3 years ago
Why do covalent bonds form between elements with similar electronegativity?
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A COVALENT BOND, FORMS BETWEEN ELEMENTS WITH SIMILAR  ELECTRONEGATIVITY AS SHARING OF ELECTRON PAIRS BETWEEN ATOMS IS EASIER AS THEY ARE IDENTICAL.

Explanation:

Bonding atoms with similar electronegativity values form covalent bonds.

A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms.

Covalent bonds form between two nonmetal atoms with identical or relatively close electronegativity values

Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons, also it is the strength an atom has to attract a bonding pair of electrons to itself.

Pure covalent bonds result when two atoms of the same electronegativity bond. This occurs only when two atoms of the same element bond with each other.

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3 years ago
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What part of an Atom undergoes change during radioactive decay
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It is clear that the core is subject to change
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How do chemicals affect the environment?
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4 0
3 years ago
You determine the volume of your plastic bag (simulated human stomach) is 1.08 L. How many grams of NaHCO3 (s) are required to f
dsp73

Answer:

3.636 grams of sodium bicarbonate is required.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 753.5 mmHg = 0.9914 atm

(1 atm = 760 mmHg)

V = Volume of gas = 1.08 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 24.5 °C= 297.65  K

Putting values in above equation, we get:

(0.9914 atm)\times 1.08 L=n\times (0.0821L.atm/mol.K)\times 297.65K\\\\n=0.0438 mole

Percentage recovery of carbon dioxide gas =  49.4%

Actual moles of carbon dioxide formed: 49.4% of 0.0438 mole

\frac{49.4}{100}\times  0.0438 mol=0.02164 mol

2NaHCO_3\righarrow Na_2CO_3+H_2O+CO_2

According to reaction ,1 mol is obtained from 2 moles of sodium bicarbonate.

Then 0.02164 moles f carbon dioxide will be obtained from:

\frac{2}{1}\times 0.02164 mol=0.04328 mol

Mass of 0.04328 moles pf sodium bicarbonate:

0.04328 mol × 84 g/mol = 3.636 g

3.636 grams of sodium bicarbonate is required.

5 0
3 years ago
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