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Delvig [45]
3 years ago
6

The cost of 5 boxes of envelopes and 5 boxes of note paper is $25.95. two boxes of envelopes and 6 boxes of note paper cost $22.

38. find the cost of each box of envelopes and each box of note paper
Mathematics
1 answer:
ludmilkaskok [199]3 years ago
6 0
So this translates to:

5e + 5n = 25.95
2e + 6n = 22.38

One way to solve that is to multiply the top equation by 2, and the bottom equation by 5:

10e + 10n = 51.90
10e + 30n = 111.90

Then subtract the top from the bottom to get:

20n = 60

and divide by 20 to get

n = 3

So you know that note paper costs $3. Substituting that into the top equation you get:

5e + 5*3 = 25.95 or

5e + 15 = 25.95

Subtracting 15 from both sides you get:

5e = 10.95

Dividing by 5 you get:

e = $2.19
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-25 = -4r + 5 please help
Andrej [43]
-25=-4r+5
Subtract 5 to each side
-25-5=-4r+5-5
-30=-4r
Divided -4 to each side
-30/-4=-4r/-4
7.5=r
Check:
-25=-4r+5
Substitute r with 7.5
-25=-4(7.5)+5
-25=-30+5
-25=-25. As a result, r=7.5. Hope it help!
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3 years ago
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What are the mean absolute deviation and population standard deviation of this data set? Round to the nearest tenth if necessary
tekilochka [14]

Answer:

For a data set of N elements:

{x₁, x₂, ..., xₙ}

The mean is:

M = \frac{x_1 + x_2 + ... + x_n}{N}

The mean absolute deviation is:

MAD = \frac{|x_1 - M| + ... + |x_n - M|}{N}

And the population standard deviation is:

PSD = \frac{\sqrt{|x_1 - M|^2 + ... + |x_n - M|^2} }{\sqrt{N}}

In this case, our set has 5 elements, and the set is:

{2, 4, 6, 9, 14}

The mean of this set is:

M = \frac{2 + 4 + 6 + 9 + 14}{5} = 7

The mean absolute deviation is:

MAD = \frac{|2 - 7| + |4 - 7| + |6 - 7|+ |9 - 7| + |14 - 7| }{5} = 3.6

And the population standard deviation is:

PSD =  \sqrt{\frac{|2 - 7|^2 + |4 - 7|^2 + |6 - 7|^2+ |9 - 7|^2 + |14 - 7|^2 }{5}} = 4.2

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Step-by-step explanation:

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