It would be 0.2222 so it's your answer
Answer:
Minimum < Q1 < Median < Q3< Maximum
Step-by-step explanation:
Given
Minimum, Median, Maximum, Q3 and Q1
<em>See attachment for complete question</em>
Required
Order from least to greatest
In a dataset, the range is:
This implies that, the minimum is the least and the maximum is the highest of the dataset
So, we have:
Minimum < < < < Maximum
The median is the middle item; So, the above becomes
Minimum < < Median < < Maximum
In a dataset, the IQR is:
This implies that:
So, we have:
Minimum < Q1 < Median < Q3< Maximum
Answer:
a) |n -11| = 5
b) n ∈ {6, 16}
Step-by-step explanation:
The wording of the question is ridiculous. We assume it is intended to read, "The distance between two numbers is 5. One of the numbers is 11. What are the possibilities for the other?"
a) The distance between a number (n) and 11 can be written as ...
|n -11|
Since we want that distance to be 5, we can write the equation ...
|n -11| = 5
__
b) The equation resolves to two:
Adding 11 to both sides of both equations gives ...
The two solutions are n=6 and n=16.
_____
<em>Comment on the question statement</em>
Increasingly, we see curriculum materials written in Pidgin English or where the words have a meaning different from that understood by a native English speaker. It appears you are the lucky recipient of such materials, so must do occasional "interpretation". Here, it seems that "two time a number" is intended to mean "two numbers."
Multiply the two values together to get 45 * 3/5 = 135/5 = 27
What is the solution set of x2 + y2 = 26 and x − y = 6? A. {(5, -1), (-5, 1)} B. {(1, 5), (5, 1)} C. {(-1, 5), (1, -5)} D. {(5,
Rus_ich [418]
He two equations given are
x^2 + y^2 = 26
And
x - y = 6
x = y +6
Putting the value of x from the second equation to the first equation, we get
x^2 + y^2 = 26
(y + 6) ^2 + y^2 = 26
y^2 + 12y + 36 + y^2 = 26
2y^2 + 12y + 36 - 26 = 0
2y^2 + 12y + 10 = 0
y^2 + 6y + 5 = 0
y^2 + y + 5y + 5 = 0
y(y + 1) + 5 ( y + 1) = 0
(y + 1)(y + 5) = 0
Then
y + 1 = 0
y = -1
so x - y = 6
x + 1 = 6
x = 5
Or
y + 5 = 0
y = - 5
Again x = 1
So the solutions would be (-1, 5), (1 , -5). The correct option is option "C".
