To find f(-20), first figure out which piece x = -20 fits with.
Since -20 < -12, x = -20 first in the domain used by the third piece.
For f(-20), treat this function as if it was just f(x) = 3x-7.
f(-20) = 3(-20) -7
= -60 - 7
= -67
–4(6x + 3) = -12<span>(x + 10)
</span><span> -24x - 12 = -12x - 120
12x = 108
x = 9
answer
</span><span>B. x = 9</span><span>
</span>
Given:
A plane is normal to the vector = -2i+5j+k
It contains the point (-10,7,5).
To find:
The component equation of the plane.
Solution:
The equation of plane is

Where,
is the point on the plane and
is normal vector.
Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is





Therefore, the equation of the plane is
.
2.. expecting something else ?