3 years ago

For which of the following graphs would it NOT make sense to connect

Mathematics

1 answer:

marshall27 [118]3 years ago

6 0

Answer:

Step-by-step explanation:

the rest of the answers are the same and it is harder to compare if the lines are connected because you are most likely going to use a bar graph

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Pls help. No files pls. Will give brainliest.

nordsb [41]

To find f(-20), first figure out which piece x = -20 fits with.

Since -20 < -12, x = -20 first in the domain used by the third piece.

For f(-20), treat this function as if it was just f(x) = 3x-7.

f(-20) = 3(-20) -7

= -60 - 7

= -67

6 0

2 years ago

in 3 hambare sunt 168,68 t de grau , in al doilea hambar sunt cu 2,18 t mai mult decat in primul si cu 3,78 t mai putin decat in

Lyrx [107]

Answer:

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2 years ago

Solve –4(6x + 3) = –12(x + 10). A. x = 2 B. x = 9 C. x = 5 D. x = –5

sergey [27]

–4(6x + 3) = -12(x + 10)
 -24x - 12 = -12x - 120
12x = 108
x = 9

answer
B. x = 9

6 0

3 years ago

find the component equation of the plane which is normal to the vector -2i+5j+k and which contains the point (-10;7;5).

maksim [4K]

Given:

A plane is normal to the vector = -2i+5j+k

It contains the point (-10,7,5).

To find:

The component equation of the plane.

Solution:

The equation of plane is

$a(x-x_0)+b(y-y_0)+c(z-z_0)=0$

Where, $(x_0,y_0,z_0)$ is the point on the plane and $\left< a,b,c\right>$ is normal vector.

Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is

$-2(x-(-10))+5(y-7)+1(z-5)=0$

$-2(x+10)+5y-35+z-5=0$

$-2x-20+5y-35+z-5=0$

$-2x+5y+z-60=0$

$-2x+5y+z=60$

Therefore, the equation of the plane is $-2x+5y+z=60$ .

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2 years ago

What's 1+1 please tell me I need help my life depends on this

avanturin [10]

2.. expecting something else ?

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2 years ago

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