All categories

3 years ago

For which of the following graphs would it NOT make sense to connect

Mathematics

1 answer:

marshall27 [118]3 years ago

6 0

Answer:

Step-by-step explanation:

the rest of the answers are the same and it is harder to compare if the lines are connected because you are most likely going to use a bar graph

You might be interested in

A large construction company wants to review the ages of its sales representatives. A sampling of the ages of 25 sales reps are

Shalnov [3]

A histogram with frequency on the x-axis and ages on the y-axis is shown below. Then the correct option is A.

<h3>What is a histogram?</h3>

A diagram is made up of rectangles whose size is related to a variable's frequency and whose width is comparable to the training sample.

A large construction company wants to review the ages of its sales representatives.

A sampling of the ages of 25 sales reps are given:

50, 42, 32, 35, 41, 44, 24, 46, 31, 47, 36, 32, 30, 44, 22, 47, 31, 56, 28, 37, 49, 28, 42, 38, 45.

Then the histogram with frequency table is given as

Range Frequency

20 to 24 2

25 to 29 2

30 to 34 5

35 to 39 4

40 to 44 5

45 to 49 5

50 to 54 1

55 to 59 1

Then the correct option is A.

The histogram is given below.

More about the histogram link is given below.

brainly.com/question/16819077

#SPJ1

6 0

2 years ago

What are the coordinates of (2,3) after a translation of 2 units left and then a rotation of 90 in a counterclockwise rotation a

eimsori [14]

2 units left would make it be 0,3 and a rotation of 90 degrees counterclockwise about the origin would make it -3,0

3 0

3 years ago

2/3 a -1/6=1/3 <br> Solve the equation

Taya2010 [7]

Step-by-step explanation:

a=3/4

3 0

3 years ago

The mean life of a television set is 119 months with a standard deviation of 14 months. If a sample of 74 televisions is randoml

irina [24]

Answer:

50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.63$

If a sample of 74 televisions is randomly selected, what is the probability that the sample mean would differ from the true mean by less than 1.1 months

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$