Given:
and 
.
To find:
The quadrant.
Solution:
We know that,
In I quadrant, all trigonometric ratios are positive.
In II quadrant, only 
are positive and others are negative.
In III quadrant, only 
are positive and others are negative.
In IV quadrant, only 
are positive and others are negative.
We have,
and .
Here, 
is positive and 
is negative. So, 
lies in the III quadrant.
Therefore, the correct option is C, i.e., III.
Answer:
The equation would be set up as y=mx+b
Sometimes the x b and y will be switched around and you would have to subtract add or divide to place the number in slope intercept form
Answer:
√x^2-4
Step-by-step explanation:
Given the expression
√(x+2) * √(x-2)
= √(x+2)(x-2)
Expand
= √x(x)-2x+2x-2(2)
= √x^2-4
Hence the product of the expression will give √x^2-4
For x to be acceptable x^2 - 4 = 0
x^2 = 4
x = ±√4
x = ±2
Acceptable value of x are values that are greater than or equal to ±2
Answer:
-1/2(x-12)
Step-by-step explanation:
-1/2x+6=-1/2(x-12)
Answer= 42
Explanation: 7*6=42 42+6=48
