Question

CAN YOU GUYS PLEASE HELP ME?!!!!!!

Answer 1

Answer:

6) C

$-2r\left(8r+5\right):\quad -16r^2-10r\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\=-2r\cdot \:8r+\left(-2r\right)\cdot \:5\\=-2\cdot \:8rr-2\cdot \:5r\\\mathrm{Simplify}\:-2\cdot \:8rr-2\cdot \:5r:\quad -16r^2-10r$

7) B

$4a\left(a^2+7a+4\right):\quad 4a^3+28a^2+16a$

$\mathrm{Distribute\:parentheses}\\=4aa^2+4a\cdot \:7a+4a\cdot \:4\\=4a^2a+4\cdot \:7aa+4\cdot \:4a\\\mathrm{Simplify}\:4a^2a+4\cdot \:7aa+4\cdot \:4a:\quad 4a^3+28a^2+16a$

Hope this helps and have a great day!!!

$Sofia$

Answer 2

Answer:

6. −16r​^2​​−10r

7. 4a^​3​​+28a​^2​​+16a

Step-by-step explanation:

1. Expand.

−2r×8r−2r×5-2r

2.Take out the constants.

(−2×8)rr−2r×5

3. Simplify −2×8-2 to −16.

−16rr−2r×5

4. Use Product Rule: x^ax^b=x^(a+b)​​.

−16r^2−2r×5

5. Simplify 2r×5 to 10r.

−16r^2−10r

1. Expand.

4aa^2+4a×7a+4a×4

2. Use Product Rule: x^ax^b=x^(a+b).

4a^(1+2)+4a×7a+4a×4

3. Simplify 1+2 to 3.

4a^3+4a×7a+4a×4

4. Take out the constants.

4a^3+(4×7)aa+4a×4

5. Simplify 4×7 to 28.

4a^3+28aa+4a×4

6. Use Product Rule: x^ax^b=x^(a+b).

4a^3+28a^2+4a×4

7. Simplify 4a×4 to 16a.

4a^3+28a^2+16a