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Burka [1]
3 years ago
5

what is the concentration (molarity) of a solution where 149g of kcl is dissolved in enough water to get a total volume of the s

olution that is 500mls?
Chemistry
1 answer:
Anit [1.1K]3 years ago
4 0
Molar mass KCl = 74.55 g/mol

Number of moles:

mass KC / molar mass

149 / 74.55 => 1.998 moles 

Volume in liters: 500 mL / 1000 => 0.5 L 

Therefore:

M = moles / volume

M = 1.998 / 0.5

M = 3.996 mol/L⁻¹
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Electron configuration for be+2
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Answer:

atomic number of Be =4

electronic configuration :1s²2s²

but for Be2+ atomic number = 4-2 =2

electronic configuration : 1s²

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4 years ago
Britta traveled 1250 km on her road trip and used 209 L of gasoline, filling her tank atan average of 1.14 euros per liter. Pier
icang [17]

Answer:

  • Britta paid more per kilometer driven

Explanation:

<u>1) Britta:</u>

  • Distance traveled: 1,250 Km
  • Gasoline used: 209 liter
  • Gasoline price: 1.23 euros / liter

Cost per km = total cost of gasoline / distance traveled

Cost per km = gasoline used × gasoline price / distance traveled

Cost per km = 209 liter × 1.14 (euro / liter) / 1,250 km =  0.19 euro / km

<u>2) Pierce:</u>

  • Distance traveled: 1,405 km
  • Gasoline used: 175 liter
  • Gasoline price = 1.23 euros / liter

Cost per km = 175 liter × 1.23 (euro / liter) / 1,405 km =  0.15 euro / km

<u>3) Comparison:</u>

  • 0.19 > 0.15 ⇒ Britta paid more per kilometer driven
4 0
4 years ago
Which profession is likely to use a radiation shield?
pantera1 [17]
<span>Which profession is likely to use a radiation shield?
</span><span>A.)dentist
<em><u>B.)astronomer</u></em>
C.)mathematician
D.)geologist

The answer is B: Astronomer

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3 0
4 years ago
Read 2 more answers
Why chloride described as an extended structure?
Amanda [17]

Answer:

Explanation:

Examples of extended structures could include sodium chloride or diamonds. Examples of molecular-level models could include drawings, 3D ball and stick structures, or computer representations showing different molecules with different types of atoms.]

6 0
3 years ago
An ideal gas in a sealed container has an initial volume of 2.80 L. At constant pressure, it is cooled to 18.00 °C, where its
Aleks04 [339]

Answer:

T_1=-91.18\°C

Explanation:

Hello there!

In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:

\frac{T_1}{V_1}= \frac{T_2}{V_2}

Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:

T_1= \frac{T_2V_1}{V_2}\\\\T_1= \frac{(18.00+273.15)K(1.75L)}{(2.80L)}\\\\T_1=182K-273.15\\\\T_1=-91.18\°C

Best regards!

6 0
3 years ago
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