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Ket [755]
3 years ago
11

Help needed ASAP will give BRAINLIEST

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
6 0

Answer:

I think that it is B

Step-by-step explanation:

<em>Hope this helped you out! Have a great day!</em>

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8+(-3) full work thx If u can help
Kisachek [45]

Answer: 5

Step-by-step explanation:

 8+(-3)

=8-3 ⇔ you don't need to change signs when it is positive(+) outside the parenthesis

=5 ⇔ subtraction

#CarryOnLearning

5 0
3 years ago
Read 2 more answers
HELP FAST PLS !!!!
fgiga [73]

Answer:

1 True

2 c>−4

3 x<  3/2

Step-by-step explanation:

6 0
3 years ago
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Algebra 1 :
victus00 [196]

What we have been given here are two points.

f(3) = -4 is the same as (3, -4)

f(2) = 6 is the same as (2, 6)

We can then use these two points to find the equation of a line.

Step 1: Find the slope

Slope Formula: (y2 - y1) / (x2 - x1)

Slope = (6 - - 4) / (2 - 3) = (10) / (-1) = -10

Step 2: Find the y-intercept

To find the y-intercept, we'll take our slope and one of our points and plug them into slope-intercept form, then solve for b.

Slope-Intercept Form: y = mx + b

Point = (2, 6)

6 = 2(-10) + b

6 = -20 + b

b = 26

Step 3: Create the equation of the line

Now that we have the slope and y-intercept, all that's left to do is plug both of those values into slope-intercept form.

y = -10x + 26

Answer: y = -10x + 26

Hope this helps!

3 0
2 years ago
Is -4 less than or greater than -6?
Aleks [24]

Answer:

-4 is greater then -6

Step-by-step explanation:

-4 is closer to 0

3 0
2 years ago
Read 2 more answers
The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct
lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

y=\dfrac{x}{1+x}

Point P\left(1,\dfrac{1}{2}\right) lies on the curve.

Point Q\left(x,\dfrac{x}{1+x}\right) is an arbitrary point on the curve.

The slope of the secant line PQ is

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]

1. If x=0.5, then the slope is

\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333

2. If x=0.9, then the slope is

\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632

3. If x=0.99, then the slope is

\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513

4. If x=0.999, then the slope is

\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501

5. If x=1.5, then the slope is

\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2

6. If x=1.1, then the slope is

\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381

7. If x=1.01, then the slope is

\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488

8. If x=1.001, then the slope is

\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499

7 0
3 years ago
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