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Lynna [10]
3 years ago
9

What variable is represented on the y-axis?

Physics
1 answer:
gladu [14]3 years ago
8 0

Distance/ Time which means Distance is on horizontal and time is on vertical

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What is the kinetic energy of an object that has a mass of 50.0kg and a velocity of 18 m/s?
Rom4ik [11]
<h2>Answer </h2>

The kinetic energy is 8100 J.

<u>Explanation</u>

Mass is 50.0kg and velocity is 18 m/s, the kinetic energy is:

As we know the formula of kinetic energy which is K.E = ½ ( mv ^ 2 ),

mass = m = 50.0kg

velocity = v = 18 m / s,

by putting values in the formula,

K.E = ½ ( mv ^ 2 ),

K.E = ½ ( 50kg ) . ( 18 m / s ) ^ 2

K.E = ½ ( 50kg ) . ( 324 ),

=> K.E = 1/2 ( 16200 ),

=> K.E = 16200 / 2,

=> K.E = 8100J.

Hence, the kinetic energy ( K.E ) is 8100 joule ( J ).  

7 0
3 years ago
What happens to electrical energy that is used by objects in our homes? (1 point) a It is absorbed by batteries. b It is destroy
Reil [10]

Question:

<em>What happens to electrical energy that is used by objects in our homes? (1 point)</em>

<em>a It is absorbed by batteries. </em>

<em>b It is destroyed. </em>

<em>c It is stored in solar panels. </em>

<em>d It is transformed into other forms of energy.</em>

<em />

Answer:

D

3 0
3 years ago
Read 2 more answers
A moving object has a kinetic energy of 150J. what is the mass of the object if its momentum is 25kgm/s
Umnica [9.8K]

Answer:

A

hooopppee itt heeelppss

8 0
3 years ago
What amount of heat is required to raise the temperature of 200 g of water by 15°C (the specific heat of water is 1 cal/g°C)
Sergeeva-Olga [200]

Answer:

Heat energy required (Q) = 3,000 J

Explanation:

Find:

Mass of water (M) = 200 g

Change in temperature (ΔT) = 15°C

Specific heat of water (C) = 1 cal/g°C

Find:

Heat energy required (Q) = ?

Computation:

Q = M × ΔT × C

Heat energy required (Q) = Mass of water (M) × Change in temperature (ΔT) × Specific heat of water (C)

Heat energy required (Q) = 200 g × 15°C × 1 cal/g°C

Heat energy required (Q) = 3,000 J

4 0
3 years ago
Satellite A has an orbital radius 3.00 times greater than that of satellite B. Satellite B's orbital period around Earth is 120
igomit [66]

Answer:

To find the circumference (orbit) of an object, you use Pi x Diameter. 

As you have the circumference of B, you divide it by Pi to get the Diameter. 

So 120 divided by 3.141592654 = 38.2 minutes for the Diameter. 

As' radius and Diameter will be 3x greater than B. 

38.2 x 3 = 114.6 

To get back to the orbital period, times 114.6 by Pi, and you will get 360 minutes

HOPE THIS HELPS AND PLS MARK AS BRAINLIEST

THNXX :)

7 0
3 years ago
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