If Earth's axis was "straight up and down" instead of tilted, then ...
<span>-- There would be no seasons.
-- The climate at any one place would be the same all year around.
-- The days would be the same length, everywhere,
and all year around.
-- So would the nights.
-- The sun would be up a little more than 12 hours every day.
It would be down a little less than 12 hours every day.
-- At the middle of the day, the sun would be at the same height
in the sky all year around, not higher in some months and lower
in others.
-- The equator would be the only place on Earth where the sun
could ever be directly over your head.
-- If you were at the north pole or the south pole, the sun would be
down on the horizon, and it would just go around and around you
every day. It would never rise or set, and it would never get any
higher or lower.
</span>
Answer:
in left
Explanation:
Hope it will help
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On driving your motorcycle in a circle of radius 75 m on wet pavement, the fastest you can go before you lose traction, assuming the coefficient of static friction is 0.20 is 147m/s
Friction helps to maintain the slipping of the vehicle on the road hence lays a very important role.
Maximum velocity of a road with friction is given by the formula,
v = μRg
where, v is the maximum velocity
μ is the coefficient of static friction
R is the radius of the circle road
g is the acceleration due to gravity
Given,
μ = 0.20
R = 75m
g = 9.8m/s²
On substituting the given values in the above formula,
v = 0.20× 75 ×9.8
v = 147m/s
So, the Maximum velocity of the wet road is 147m/s.
Learn more about Velocity here, brainly.com/question/18084516
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Answer: 12.67 cm, 8 cm
Explanation:
Given
Normal distance of separation of eyes, d(n) = 6 cm
Distance of separation is your eyes, d(y) = 9.5 cm
Angle created during the jump, θ = 0.75°
To solve this, we use the formula,
θ = d/r, where
θ = angle created during the jump
d = separation between the eyes
r = distance from the object
θ = d/r
0.75 = 9.5 / r
r = 9.5 / 0.75
r = 12.67 cm
θ = d/r
0.75 = 6 / r
r = 6 / 0.75
r = 8 cm
Thus, the object is 12.67 cm far away in your own "unique" eyes, and just 8 cm further away to the normal person eye
