Answer:
0.647 nC
Explanation:
The force experienced by a charge due to the presence of an electric field is given by
where
q is the charge
E is the magnitude of the electric field
In this problem, each antenna is modelled as it was a single point charge, experiencing a force of
Therefore, if the electric field magnitude is
Then the charge on each antenna would be
Answer:
electrons can be knocked loose from one object and picked up by the other. The object that gains electrons becomes negatively charged, while the object that loses electrons becomes positively charged.
Given Information:
Force = f = 1 pound
Stretched length = x = 0.1 ft
Required Information:
Work done = W = ?
Answer:
Work done = 6.05 ft.lb
Explanation:
From the Hook's law we know that
f(x) = kx
Where f is the applied force, k is spring constant and x is length of spring being stretched.
k = F/x
k = 1/0.1
k = 10 lb/ft
f(x) = 10x
The work done is given by
W = ∫ f(x) dx
Where f(x) = 10x and limits of integration are (1.1, 0)
W = ∫ 10x dx
W = 10*x²/2
W = 5x²
Evaluating the limits,
W = 5(1.1)² - 5(0)²
W = 6.05 - 0
W = 6.05 ft.lb
Therefore, 6.05 ft.lb work has been done in stretching the spring from its natural length to 1.1 feet beyond it's natural length.
Like bad energy
Scientific energy
Um thats all i got sry
Potential energy increases as speed decreases. Kinetic increases when speed increases.