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BabaBlast [244]
3 years ago
9

during a test crash an airbag inflates to stop a dummies forward motion. the dummies mass is 75 kg. if the net force on the dumm

y is 825N toward the rear of the car what is the dummies deceleration
Physics
2 answers:
marta [7]3 years ago
6 0

Answer:

Dummies deceleration is 11m/s²

Explanation:

According to Newton's second law, the relationship between the force applied to an object, its mass, and the acceleration (or deceleration) caused, is given by:

F=ma

Solving for acceleration:

a=\frac{F}{m}

If we plug in the vales (taking into account the negative sign of the force, as its directed backwards):

a=\frac{-825N}{75kg}=-11m/s^2

a=-11m/s^2

Deceleration is simply the magnitude of negative acceleration. Therefore, dummies deceleration is 11m/s²

den301095 [7]3 years ago
5 0
Use Force=Mass x Acceleration (newtons second law states force is directly proportional to the acceleration) so you can say that the force is negative and solve for Acceleration.
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A warehouse worker is pushing a 90.0-kg crate with a horizontal force of 282 N at a speed of v = 0.850 m/s across the warehouse
Elanso [62]

Answer:

v_{f} = 0.51 \frac{m}{s}

Explanation:

We apply Newton's second law at the crate :

∑F = m*a (Formula 1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Data:

m=90kg :  crate mass

F= 282 N

μk =0.351 :coefficient of kinetic friction

g = 9.8 m/s² : acceleration due to gravity

Crate weight  (W)

W= m*g

W= 90kg*9.8 m/s²

W= 882 N

Friction force : Ff

Ff= μk*N Formula (2)   

μk: coefficient of kinetic friction

N : Normal force (N)  

Problem development

We apply the formula (1)

∑Fy = m*ay    , ay=0

N-W = 0

N = W

N = 882 N

We replace the  data in the formula (2)

Ff= μk*N  = 0.351* 882 N

Ff=  309.58 N

We apply the formula (1) in x direction:

∑Fx = m*ax    , ax=0

282 N - 309.58 N = 90*a  

a=  (282 N - 309.58 N ) / (90)

a= - 0.306 m/s²

Kinematics of the crate

Because the crate moves with uniformly accelerated movement we apply the following formula :

vf²=v₀²+2*a*d Formula (3)

Where:  

d:displacement in meters (m)  

v₀: initial speed in m/s  

vf: final speed in m/s  

a: acceleration in m/s²

Data

v₀ = 0.850 m/s

d = 0.75 m

a= - 0.306 m/s²

We replace the  data in the formula (3)

vf²=(0.850)²+(2)( - 0.306 )(0.75 )

v_{f} = \sqrt{(0.850)^{2} +(2)( - 0.306 )(0.75 )}

v_{f} = 0.51 \frac{m}{s}

8 0
3 years ago
A spring has a spring constant of 800 N/m. How much work must be done to stretch the spring 0.4 m from its unstretched position?
Sunny_sXe [5.5K]

Answer:

A. 64.0 J

Explanation:

Given parameters:

Spring constant  = 800N/m

Extension  = 0.4m

Unknown:

Work done  = ?

Solution:

The work done in a string is given as:

       

         Work done  = \frac{1}{2} x 800 x 0.4²   = 64J

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A car that travels from point A to point B in four hours, and then from point B back to point A in six hours. The road between p
Hitman42 [59]
Note : Be careful with speed and velocity, even the formula is same that v =  \frac{x}{t}

1. If we would like to find the velocity, we must calculate the distance from initial to final, x_{f} -  x_{i} = (delta)x,

2. If we would like to find the speed, we must calculate the total distance that travelled (x_{total}.

So, in this question, because it return back to its initial point so (delta)x = 0, so average velocity is 0 m/s.
3 0
3 years ago
Read 2 more answers
Two power lines, each 290 m in length, run parallel to each other with a separation of 23 cm. If the lines carry parallel curren
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To solve this problem we will apply the concepts related to the Magnetic Force, which is defined as the product between the currents multiplied by the length where they are transmitted and inversely proportional to the distance that separates them, considering between them, the costs indicated below . We will simply replace the values and obtain the desired value,

F = \frac{\mu_0 I_1I_2 l }{2\pi d}

Here,

\mu_0 = Permeability of free space

I_{1,2} = Current at each state

l = Length

d = Distance of separation

Replacing with our values we have that the force is,

F = \frac{(4\pi *10^{-7})(120)(120)(290)}{2\pi (0.23)}

F = 3.63N

Therefore the magnitude of the force is 3.63N, and  if the currents are in same direction then force is attractive, while if the currents are in opposite direction then force is repulsive ( force is same).

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A ball was positioned in the middle of a smooth ramp and allowed to roll
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Answer:

These are all the forces acting on the ball: friction, gravity, and a normal force.

Explanation:

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