Answer:

Explanation:
We apply Newton's second law at the crate :
∑F = m*a (Formula 1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Data:
m=90kg : crate mass
F= 282 N
μk =0.351 :coefficient of kinetic friction
g = 9.8 m/s² : acceleration due to gravity
Crate weight (W)
W= m*g
W= 90kg*9.8 m/s²
W= 882 N
Friction force : Ff
Ff= μk*N Formula (2)
μk: coefficient of kinetic friction
N : Normal force (N)
Problem development
We apply the formula (1)
∑Fy = m*ay , ay=0
N-W = 0
N = W
N = 882 N
We replace the data in the formula (2)
Ff= μk*N = 0.351* 882 N
Ff= 309.58 N
We apply the formula (1) in x direction:
∑Fx = m*ax , ax=0
282 N - 309.58 N = 90*a
a= (282 N - 309.58 N ) / (90)
a= - 0.306 m/s²
Kinematics of the crate
Because the crate moves with uniformly accelerated movement we apply the following formula :
vf²=v₀²+2*a*d Formula (3)
Where:
d:displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
Data
v₀ = 0.850 m/s
d = 0.75 m
a= - 0.306 m/s²
We replace the data in the formula (3)
vf²=(0.850)²+(2)( - 0.306 )(0.75 )


Answer:
A. 64.0 J
Explanation:
Given parameters:
Spring constant = 800N/m
Extension = 0.4m
Unknown:
Work done = ?
Solution:
The work done in a string is given as:
Work done =
x 800 x 0.4² = 64J
Note : Be careful with speed and velocity, even the formula is same that

1. If we would like to find the velocity, we must calculate the distance from initial to final,

,
2. If we would like to find the speed, we must calculate the total distance that travelled (

.
So, in this question, because it return back to its initial point so (delta)x = 0, so average velocity is 0 m/s.
To solve this problem we will apply the concepts related to the Magnetic Force, which is defined as the product between the currents multiplied by the length where they are transmitted and inversely proportional to the distance that separates them, considering between them, the costs indicated below . We will simply replace the values and obtain the desired value,

Here,
= Permeability of free space
= Current at each state
= Length
= Distance of separation
Replacing with our values we have that the force is,


Therefore the magnitude of the force is 3.63N, and if the currents are in same direction then force is attractive, while if the currents are in opposite direction then force is repulsive ( force is same).
Answer:
These are all the forces acting on the ball: friction, gravity, and a normal force.
Explanation: