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BabaBlast [244]
3 years ago
9

during a test crash an airbag inflates to stop a dummies forward motion. the dummies mass is 75 kg. if the net force on the dumm

y is 825N toward the rear of the car what is the dummies deceleration
Physics
2 answers:
marta [7]3 years ago
6 0

Answer:

Dummies deceleration is 11m/s²

Explanation:

According to Newton's second law, the relationship between the force applied to an object, its mass, and the acceleration (or deceleration) caused, is given by:

F=ma

Solving for acceleration:

a=\frac{F}{m}

If we plug in the vales (taking into account the negative sign of the force, as its directed backwards):

a=\frac{-825N}{75kg}=-11m/s^2

a=-11m/s^2

Deceleration is simply the magnitude of negative acceleration. Therefore, dummies deceleration is 11m/s²

den301095 [7]3 years ago
5 0
Use Force=Mass x Acceleration (newtons second law states force is directly proportional to the acceleration) so you can say that the force is negative and solve for Acceleration.
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Answer:

0 Kelvin

Explanation:

Atoms in absolute temperature get approximatelly motionless since 0 Kelvin is -273 degrees Celcius. The kinetic energy of atoms/particles in matter has the possible lowest value ( almost zero), so that there is nothing colder than 0 Kelvin.

4 0
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The first ionization energy of a hydrogen atom is 2.18 aj (attojoules). what is the frequency and wavelength, in nanometers, of
jasenka [17]

1) Frequency: 3.29\cdot 10^{15}Hz

the energy of the photon absorbed must be equal to the ionization enegy of the atom, which is

E=2.18 aJ=2.18\cdot 10^{-18} J

The energy of a photon is given by

E=hf

where h=6.63\cdot 10^{-34}Js is the Planck's constant. By using the energy written above and by re-arranging thsi formula, we can calculate the frequency of the photon:

f=\frac{E}{h}=\frac{2.18\cdot 10^{-18} J}{6.63\cdot 10^{-34} Js}=3.29\cdot 10^{15} Hz


2) Wavelength: 91.2 nm

The wavelength of the photon can be found from its frequency, by using the following relationship:

\lambda=\frac{c}{f}

where c=3\cdot 10^8 m/s is the speed of light and f is the frequency. Substituting the frequency, we find

\lambda=\frac{3\cdot 10^8 m/s}{3.29\cdot 10^{15}Hz}=9.12\cdot 10^{-8} m=91.2 nm

5 0
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Sever21 [200]
(A) noble gases / group 18
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Data given:

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Data needed:

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Solution:

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