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sweet-ann [11.9K]
3 years ago
12

According to the Kinetic Molecular Theory, the absolute temperature of a gas is directly related to average molecular kinetic __

_________.
law
energy
volume
temperature
Chemistry
2 answers:
dezoksy [38]3 years ago
5 0
Kinetic (energy) would be your answer.
Ludmilka [50]3 years ago
4 0
The absolute temperature of a gas is directly related to average molecular kinetic Energy law.
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3 years ago
Using the Lewis dot structures of magnesium and oxygen, predict the ionic formula
Blizzard [7]

Answer:

(edit: nvm I figured it out, here is the answer)

Explanation:

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3 years ago
When .50 mL of 2.0M Li3PO4 is added to 50 mL of 1.0 M LiH2PO4 what is the resulting concentration of Li+?
jeka57 [31]
Hence the resulting concentration of Li+ is 1M. Hope it helps.

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3 years ago
The solubility of NaCH3CO2 in water is ~1.23 g/mL. What would be the best method for preparing a supersaturated NaCH3CO2 solutio
Len [333]

Answer:

b) add 130 g of NaCH₃CO₂ to 100 mL of H₂O at 80 °C while stirring until all the solid dissolves, then let the solution cool to room temperature.

Explanation:

The solubility of NaCH₃CO₂ in water is ~1.23 g/mL. This means that at room temperature, we can dissolve 1.23 g of solute in 1 mL of water (solvent).

<em>What would be the best method for preparing a supersaturated NaCH₃CO₂ solution?</em>

<em>a) add 130 g of NaCH₃CO₂ to 100 mL of H₂O at room temperature while stirring until all the solid dissolves.</em> NO. At room temperature, in 100 mL of H₂O can only be dissolved 123 g of solute. If we add 130 g of solute, 123 g will dissolve and the rest (7 g) will precipitate. The resulting solution will be saturated.

<em>b) add 130 g of NaCH₃CO₂ to 100 mL of H₂O at 80 °C while stirring until all the solid dissolves, then let the solution cool to room temperature. </em>YES. The solubility of NaCH₃CO₂ at 80 °C is ~1.50g/mL. If we add 130 g of solute at 80 °C and let it slowly cool (and without any perturbation), the resulting solution at room temperature will be supersaturated.

<em>c) add 1.23 g of NaCH₃CO₂ to 200 mL of H₂O at 80 °C while stirring until all the solid dissolves, then let the solution cool to room temperature.</em> NO. If we add 1.23 g of solute to 200 mL of water, the resulting solution will have a concentration of 1.23 g/200 mL = 0.00615 g/mL, which represents an unsaturated solution.

5 0
3 years ago
Two molecules that can cross a lipid bilayer without help from membrane proteins are o2 and co2. what property allows this to oc
Dennis_Churaev [7]
Two molecules that can cross a lipid bilayer without help from membrane proteins are oxygen and carbon dioxide. The property that allows this to happen is that both oxygen and carbon dioxide molecules are nonpolar which means that they can pass easily through the hydrophobic part of the membrane. The lipid bilayer is present in all cell membranes. It consists of two layers of the fat cells which are arranged into two sheets. It functions as a barrier which marks the boundaries of the cell. The inner part of a lipid bilayer is nonpolar since it is composed of the hydrophobic end of the phospholopids. 
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