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4 years ago

why do we heat the test tube in a glass beaker during a chemistry experiment and not directly over a flame?

1 answer:

7 0

It is not directly over a flame because it depends on the substance you might not want to heat it too much.you never know what could happen

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Which kind of force is a dipole-dipole force?

dexar [7]

Answer:

Explanation:

Types of Attractive Intermolecular Forces. Dipole-dipole forces: electrostatic interactions of permanent dipoles in molecules; includes hydrogen bonding.

This is all I can think of, I hope this has helped you.

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3 years ago

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Which energy source can we can find waste everywhere and shouldn’t run out?

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Answer:

wind

Explanation:

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Suppose you have made the following hypothesis:

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There are less sharks farther from coral reefs.

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Briefly describe the intermolecular forces present in your unknown

Korvikt [17]

An inter-molecular power is basically an alluring power between neighboring particles. There are three regular sorts of inter-molecular power: lasting dipole-dipole powers, hydrogen bonds and van der Waals' powers.

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3 years ago

Compounds A, B, and C react according to the following equation. 3A(g) + 2B(g) 2C(g) At 100°C a mixture of these gases at equili

Vedmedyk [2.9K]

Answer:

The value of Kc for the reaction is 3.24

Explanation:

A reversible chemical reaction, indicated by a double arrow, occurs in both directions: reagents transforming into products ( direct reaction) and products transforming back into reagents (inverse reaction)

Chemical Equilibrium is the state in which direct and indirect reactions have the same reaction rate. Then taking into account the rate constant of a direct reaction and its inverse the chemical constant Kc is defined.

Being:

aA + bB ⇔ cC + dD

where a, b, c and d are the stoichiometric coefficients, the equilibrium constant with the following equation:

$Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }$

Kc is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reagents also raised to their stoichiometric coefficients.

Then, in the reaction 3A(g) + 2B(g) ⇔ 2C(g), the constant Kc is:

$Kc=\frac{[C]^{2} }{[A]^{3} *[B]^{2} }$

where:

[A]= 0.855 M
[B]= 1.23 M
[C]= 1.75 M

Replacing:

$Kc=\frac{1.75^{2} }{0.855^{3}*1.23^{2} }$

Solving you get:

Kc=3.24

<u><em>The value of Kc for the reaction is 3.24</em></u>

8 0

3 years ago