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Anuta_ua [19.1K]
3 years ago
7

Determine the molar mass of the ionic compound sodium hydroxide. (1 point)

Chemistry
1 answer:
dybincka [34]3 years ago
3 0
Sodium - 22.989 - 23
Hydrogen - 1.007 - 1
Oxygen - 15.9994 -16
NaOH - 39.997- 40

It is 39.997 but when rounded it is 40

Hope this helps :)

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Addition of an excess of lead (II) nitrate to a 50.0mL solution of magnesium chloride caused a formation of 7.35g of lead (II) c
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Answer:

[Cl⁻] = 0.016M

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First of all, we determine the reaction:

Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓  +  Mg(NO₃)₂(aq)

This is a solubility equilibrium, where you have a precipitate formed, lead(II) chloride. This salt can be dissociated as:

           PbCl₂(s)  ⇄  Pb²⁺ (aq)  +  2Cl⁻ (aq)     Kps

Initial        x

React       s

Eq          x - s              s                  2s

As this is an equilibrium, the Kps works as the constant (Solubility product):

Kps = s . (2s)²

Kps = 4s³ = 1.7ₓ10⁻⁵

4s³ = 1.7ₓ10⁻⁵

s =  ∛(1.7ₓ10⁻⁵ . 1/4)

s = 0.016 M

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