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My name is Ann [436]
2 years ago
14

What would happen if the sand dunes in an area were destroyed?

Chemistry
2 answers:
Andru [333]2 years ago
4 0

Answer:

Then everything around the sand dunes are destroyed. It's like a domino effect.

Explanation:

Komok [63]2 years ago
3 0

Answer:

<u>Our beaches would be unprotected</u>

In the short-term, these artificial sand hills will be destroyed by the elements. Because sand dunes protect inland areas from swells, tides, and winds, they must be protected and defended like national treasures. ... The ocean and the wind can have an unpredictable, destructive force on coastal regions.

- surfertoday

Natural sand dunes play a vital role in protecting our beaches, coastline and coastal developments from coastal hazards such as erosion, coastal flooding and storm damage. Sand dunes protect our shorelines from coastal erosion and provide shelter from the wind and sea spray.

- Waikato Regional Council

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How do electrons in a metallic bond behave?
igomit [66]

Hello,

In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “sea” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions.

Hope this helps!!!! Happy Holidays!!!! (:

4 0
3 years ago
Using the Rydberg formula, calculate the initial energy level when an electron in a hydrogen atom transitions into n= 2 and emit
EleoNora [17]

Answer:

1

Explanation:

Using the Rydberg formula as:

\frac {1}{\lambda}=R_H\times Z^2\times (\frac {1}{n_{1}^2}-\frac {1}{n_{2}^2})

where,

λ is wavelength of photon

R = Rydberg's constant (1.097 × 10⁷ m⁻¹)

Z = atomic number of atom

n₁ is the initial final level and n₂ is the final energy level

For Hydrogen atom, Z= 1

n₂ = 2

Wavelength = 410.1 nm

Also,

1 nm = 10⁻⁹ m

So,

Wavelength = 410.1 × 10⁻⁹ m

Applying in the formula as:

\frac {1}{410.1\times 10^{-9}}=1.097\times 10^7\times 1^2\times (\frac {1}{n_{1}^2}-\frac {1}{2^2})

Solving for n₁ , we get

n₁ ≅ 1

3 0
3 years ago
Read 2 more answers
State the law of multiple proportions.
Fofino [41]
Statement that when two elements combine with each other to from more than one compound, the weights of one element that combine with a fixed weight of the other are in a ratio of small whole numbers.
8 0
3 years ago
Read 2 more answers
2. What are the factors that influence the two types of energy?
VikaD [51]

Answer:

It depends on the objects mass, the gravitational pull when up or down slopes, and the height of the reference point

3 0
2 years ago
Compute the values. Express these answers to the hundredths place (i.e., two digits after the decimal point). log ( 2.1 ) = ln (
zepelin [54]

Answer:

x = 4.17

y = 1.86

Explanation:

0.62 = log(x)

x = 10^0.62 = 4.17 ( to the nearest hundredth)

0.62 = ln(y)

y = e^0.62 = 1.86 (to the nearest hundredth)

8 0
3 years ago
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