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aleksandrvk [35]
3 years ago
6

Let f(x)=3x^2-x+2 and g(x)= 5x^2-1. find f(g(x))

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
7 0

Answer:

15x^4-5x^2+1

Step-by-step explanation:

g(x)=5x^2-1 and f(x)=3x^2-x+2

f(g(x))would mean that g(x) would be x in f(x).

So f(g(x) would be 15x^4-3-5x^2+1+2

simplified would be 15x^4-5x^2+1

LenKa [72]3 years ago
3 0
F (5x^2 - 1) = 75x^4 - 35x^2 + 6
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Read 2 more answers
Write an equation for the quadratic graphed below: x-intercepts: (-1,0) and (4,0); y-intercept: (0,1)
Luda [366]

Answer:

y = (1/4)x² - (5/4)x + 1

Step-by-step explanation:

The x-intercepts of the quadratic equation are simply it's roots.

Thus, we have;

(x + 1) = 0 and (x - 4) = 0

Now, formula for quadratic equation is;

y = ax² + bx + c

Where c is the y intercept.

At y-intercept: (0,1), we have;

At (-1,0), thus;

0 = a(1²) + b(1) + 1

a + b = -1 - - - (1)

At (4,0), thus;

0 = a(4²) + b(4) + 1

16a + 4b = -1

Divide both sides by 4 to get;

4a + b = -1/4 - - - (2)

From eq 1, b = -1 - a

Thus;

4a + (-1 - a) = -1/4

4a - 1 - a = -1/4

3a - 1 = -1/4

3a = 1 - 1/4

3a = 3/4

a = 1/4

b = -1 - 1/4

b = -5/4

Thus;

y = (1/4)x² - (5/4)x + 1

6 0
2 years ago
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