All categories

3 years ago

The question is: find 55% of $4.80...how do I find the answer?

Mathematics

2 answers:

tresset_1 [31]3 years ago

6 0

4.80 = 100%
x = 55%

Cross Multiply

100 * x = 55 * 4.80
100x = 264
x = <u>264</u>
100
x = 2.64

Solution: $2.64

EleoNora [17]3 years ago

3 0

Percentages are out of one, so finding the x% of anything is just multiplying that thing by some decimal value defined by x. In this case, since x is 55, you multiply by .55. If it was 5%, you would multiply by .05, 34% .34, and so on. 4.8*.55=2.64.

You might be interested in

I had trouble plotting the midpoint lol but can someone plz help me :c

kodGreya [7K]

midpoint is (-1 and -1.5)

8 0

3 years ago

Read 2 more answers

Find the modulus of the complex number 6-2i

Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

Step-by-step explanation:

Given the number

$6-2i$

We know that

$z = x + iy$

where x and y are real and $\sqrt{-1}=i$

The modulus or absolute value of z is:

$|z|\:=\sqrt{x^2+y^2}$

Therefore, the modulus of $6-2i$ will be:

$z=6-2i$

$z=6+(-2)i$

$|z|\:=\sqrt{x^2+y^2}$

$|z|\:=\sqrt{6^2+\left(-2\right)^2}$

$=\sqrt{6^2+2^2}$

$=\sqrt{36+4}$

$=\sqrt{40}$

$=\sqrt{2^2}\sqrt{2\cdot \:5}$

$=2\sqrt{2\cdot \:5}$

$=2\sqrt{10}$

Therefore, the modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

3 0

3 years ago

Nonzero multiples of 12 and 15

Viefleur [7K]

3 is a common multiple .. (3x4=12....3x5=15)

5 0

3 years ago

Which function is the inverse of f (x) = 2x + 8?

tiny-mole [99]

Answer:

f-1(x) = (x-8)/2

Step-by-step explanation:

f(x) = 2x+ 8

y = 2x + 8

replacing y and x

x = 2y + 8

2y = x- 8

y =( x-8)/2

f-1 (x) =( x-8)/2

3 0

3 years ago

A professor at a local university noted that the exam grades of her students were normally distributed with a mean of 73 and a s

jasenka [17]

Answer:

The minimum score of those who received C's is 67.39.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 73, \sigma = 11$