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2 years ago

The question is: find 55% of $4.80...how do I find the answer?

Mathematics

2 answers:

tresset_1 [31]2 years ago

6 0

4.80 = 100%
x = 55%

Cross Multiply

100 * x = 55 * 4.80
100x = 264
x = 264
100
x = 2.64

Solution: $2.64

EleoNora [17]2 years ago

3 0

Percentages are out of one, so finding the x% of anything is just multiplying that thing by some decimal value defined by x. In this case, since x is 55, you multiply by .55. If it was 5%, you would multiply by .05, 34% .34, and so on. 4.8*.55=2.64.

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William purchased 76.9 feet of fencing for his back yard. He realized after measuring, that he still needed an additional 25.7 f

Lostsunrise [7]

William needs 102.6 fencing in all because 76.9 plus 25.7 equals 102.6, hope this helps!

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2 years ago

A salad dressing cars for three parts oil and one part vinegar Addy uses Tuesday but spoons of vinegar and 6 tablespoons of oil

Natasha2012 [34]

Answer:

The quantities used by Manuela were correct

Step-by-step explanation:

The question is

Did Manuela use the right quantities?

Let

x -----> the parts of oil

y ----> the parts of vinegar

we know that

The ratio of the parts of oil by the parts of vinegar of recipe is

Determine the relation used by Manuela

Compare with the recipe

Is true, the quantities are proportional

therefore

The quantities used by Manuela were correct

4 0

2 years ago

Parallel / Perpendicular Practice

deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

Neither
║
Neither
⊥
║
Neither
Neither
Neither

Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; $m_1 = -\dfrac{1}{m_2}$

1. The given equations are in the slope and intercept form

$\ y = 3 \cdot x + 1$

The slope, m₁ = 3

$y = \dfrac{1}{3} \cdot x + 1$

The slope, m₂ = $\dfrac{1}{3}$

Therefore, the equations are neither parallel or perpendicular

Neither

2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

$y = 5 \cdot x -\dfrac{7}{2}$

Therefore, the two equations are parallel

3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

$y = 2 -\dfrac{1}{2} \cdot x$

Slope, m₁ = $-\dfrac{1}{2}$

$y = \dfrac{1}{2} \cdot x - 2$

Slope, m₂ = $\dfrac{1}{2}$

The slopes

Therefore, m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

The lines are Neither parallel nor perpendicular

Neither

4. The given equations are;

2·y - x = 2

$y = \dfrac{1}{2} \cdot x +1$

m₁ = $\dfrac{1}{2}$

y = -2·x + 4

m₂ = -2

Therefore;

$m_1 \neq -\dfrac{1}{m_2}$

Therefore, the lines are perpendicular

5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, $y = \dfrac{3}{4} \cdot x + 3$

Second equation, $y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}$

Therefore, m₁ = m₂, the lines are parallel

6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

5·y - 10 = 3, therefore, y = $\dfrac{13}{5}$

Therefore, the two equations are neither parallel nor perpendicular

Neither

7. The equations are;

2·x + 6·y = -3

Which gives $y = -\dfrac{1}{3} \cdot x - \dfrac{1}{2}$

12·y = 4·x + 20

Which gives

$y = \dfrac{1}{3} \cdot x + \dfrac{5}{3}$

m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

Neither

8. 2·x - 5·y = -3

Which gives; $y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}$

5·x + 27 = 6

$x = -\dfrac{21}{5}$

Therefore, the slopes are not equal, or perpendicular, the correct option is Neither

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3 years ago

Solving systems of equations by substitution Y=6x y=5x+7

soldi70 [24.7K]

Y=6x (1)
y=5x-7 (2)

Substitute y into (2)
(6x)=5x-7 -- subtract 5x from both sides
x=-7

Sub x into 1
y=6(-7)
y=-42

x=-7
y=-42

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3 years ago

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