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Ilia_Sergeevich [38]

2 years ago

15

Light can be transmitted through long fiber optic strands because of

2 answers:

Paraphin [41]2 years ago

8 0

Answer: light can transmitted through long fiber optic strand as a result of total internal reflection

Explanation:

Total internal reflection occur when a right ray incident at the interface of two less dense media is completely reflected back to a denser medium, as a result of a greater angle than the critical angle.

Optical fibers use total internal reflection to transmit light. Light passing through the inner core of the optical fiber strand is reflected back rather than being refracted to the cladding.

Note: the optic fiber is made of dense solid glass core (the inner) surrounded by less dense cladding (outer)

wariber [46]2 years ago

3 0

Total internal reflection. Although I'm not 100%

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What is the capital of prince edward island

Anni [7]

Answer:

The capital of Prince Edward Island is Charlottetown.

Explanation:

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a 100 N block on a 30 incline, is being held motionless by friction. The coefficient of static friction between the block and th

nirvana33 [79]

The answer would be 50N

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A charge of 6.7 × 10^-15 coulombs is located at a point where its potential energy is 5.6 × 10^-12 joules. What is the electric

natita [175]

Answer:

C. 8.4 × 10^2 volts

Explanation:

The potential energy of a charge is given by:

$U=qV$

where

q is the magnitude of the charge

V is the electric potential

In this problem, we have

$q=6.7\cdot 10^{-15} C$ is the charge

$U=5.6\cdot 10^{-12} J$ is the potential energy

Re-arranging the formula and using these numbers, we can find the electric potential:

$V=\frac{U}{q}=\frac{5.6\cdot 10^{-12} J}{6.7\cdot 10^{-15} C}=835.8 V = 8.4\cdot 10^2 V$

4 0

3 years ago

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Two resistances, R1 and R2, are connected in series across a 12-V battery. The current increases by 0.500 A when R2 is removed,

KATRIN_1 [288]

Answer:

a) R₁ = 14.1 Ω, b) R₂ = 19.9 Ω

Explanation:

For this exercise we must use ohm's law remembering that in a series circuit the equivalent resistance is the sum of the resistances

all resistors connected

V = i (R₁ + R₂)

with R₁ connected

V = (i + 0.5) R₁

with R₂ connected

V = (i + 0.25) R₂

We have a system of three equations with three unknowns for which we can solve it

We substitute the last two equations in the first

V = i ( $\frac{V}{ i+0.5} + \frac{V}{i+0.25}$ )

1 = i ( $\frac{1}{i+0.5} + \frac{1}{i+0.25}$ )

1 = i ( $\frac{i+0.5+i+0.25}{(i+0.5) \ ( i+0.25) }$ ) = $\frac{i^2 + 0.75i}{i^2 + 0.75 i + 0.125}$

i² + 0.75 i + 0.125 = 2i² + 0.75 i

i² - 0.125 = 0

i = √0.125

i = 0.35355 A

with the second equation we look for R1

R₁ = $\frac{V}{i+0.5}$

R₁ = 12 /( 0.35355 +0.5)

R₁ = 14.1 Ω

with the third equation we look for R2

R₂ = $\frac{V}{i+0.25}$

R₂ = $\frac{12}{0.35355+0.25}$

R₂ = 19.9 Ω

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