Answer:
45.89m/s²
Explanation:
Given
Distance S = 305m
Time t = 3.64s
To get the acceleration during this run, we will apply the equation of motion:
S = ut+1/2at²
Substitute the given parameters into the formula and calculate the value of a
305 = 0+1/2 a(3.64)²
304 = 1/2(13.2496)a
304 = 6.6248a
a = 304/6.6248
a = 45.89m/s²
Hence the average acceleration during this run is 45.89m/s²
Answer:
from the position of the center of the Sun
Explanation:
As we know that mass of Sun and Jupiter is given as
distance between Sun and Jupiter is given as
now let the position of Sun is origin and position of Jupiter is given at the position same as the distance between them
so we will have
from the position of the center of the Sun
Average velocity = (x( 2.08 ) - x ( 0 )) / ( 2.08 s - 0 s )
x ( 2.08 ) = 1.42 * 2.08² - 0.05 * 2.08³ =
= 1.42 * 4.3264 - 0.443456 = 6.143484 - 0.443456 ≈ 5.7 m
v = ( 5.7 m - 0 m) / (2.08 s - 0 s ) = 5.7 / 2.08 m/s = 27.4 m/s
Answer:
The correct answer is - Plantae.
Explanation:
Drosera m<em>agnifica</em> is discovered in 2015 for the first time and the characteristics this organism's cell shows are -
- permanent vacuoles
- surrounded by cellulose layer
Vacuoles are present in both Plantae and Animalia kingdom of the eukaryotic organism but in animal cells, there are small and numerous vacuoles present and they are not permanent whereas in plant cells vacuoles are present permanently.
The cell of an animal cell has no surrounding layer other than cell membrane while in the plant cell there is a supporting and protecting layer of cellulose cell wall present.
On the basis of the given characteristics, it is confirmed that the Drosera magnifica belongs to Plantae kingdom.
