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3 years ago

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We have starin which is 0.4 and area is 0.05 what is sigma

1 answer:

Eddi Din [679]3 years ago

5 0

<span>normal stress, shear stress, bulk stress, normal </span>strain<span>, shear </span>strain<span>, bulk </span>strain, ... The symbol for stress is often the Greek letter "sigma"<span> Stress </span>has<span> the units of force over </span>area<span> i.e. N/m</span>2<span> which is given the special name Pascal. ... 5.7. </span>0.4<span>. polystyrene. 3.8. 1.0. 4.7. </span>0.4<span>. polyethylene. 0.14. </span>0.05<span>. 0.35. </span>0.4<span> ...</span>

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the number of electrons in a copper penny is approximately 10 10^23. How large would the force be on an object if it carried thi

iVinArrow [24]

Answer:

0.000230144 N

Explanation:

n = Number of electrons = $10\times 10^{23}$

q = Charge of electron = $1.6\times 10^{-19}\ C$

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

r = Distance between obects = 1 m

The force would be

$F=\dfrac{nkq^2}{r^2}\\\Rightarrow F=\dfrac{10\times 10^{23}\times 8.99\times 10^9\times (1.6\times 10^{-19})^2}{1^2}\\\Rightarrow F=0.000230144$

The force would be 0.000230144 N

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3 years ago

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JulsSmile [24]

Answer:

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Explanation:

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Read 2 more answers

If a boy (m = 25 kg) at rest on skates is pushed by another boy who exerts a force of 500 N on him and if the first boy's final

Bond [772]

Answer:

1 second

Explanation:

The impulse exerted on the boy is equal to its change of momentum:

$I = \Delta p\\F \Delta t = m \Delta v$

where

F = 500 N is the push on the boy

$\Delta t$ is the contact time

m = 25 kg is the mass of the boy

$\Delta v = 20 m/s$ is the change in velocity of the boy

Solving the formula for the contact time, we find

$\Delta t=\frac{m\Delta v}{F}=\frac{(25 kg)(20 m/s)}{500 N}=1 s$

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