Answer:
Explanation:
Capacitor of 0.75μF, charged to 70V and connect in series with 55Ω and 140 Ω to discharge.
Energy dissipates in 55Ω resistor is given by V²/R
Since the 55ohms and 140ohms l discharge the capacitor fully, the voltage will be zero volts and this voltage will be shared by the resistor in ratio.
So for 55ohms, using voltage divider rule
V=R1/(R1+R2) ×Vt
V=55/(55+140) ×70
V=19.74Volts is across the 55ohms resistor.
Then, energy loss will be
E=V²/R
E=19.74²/55
E=7.09J
7.09J of heat is dissipated by the 55ohms resistor
Answer:
the force of the friction is A-0.52
<u>Mechanics</u> is the branch of physics which deals with the study of motion of material objects.
<u><em>Divisions</em></u>
There are three major division of mechanics
Statics
Kinematics
Dynamics.
Current flow depends on other things in addition to the circuit configuration.
If the SAME voltage is applied to some arrangement of the SAME components, the greatest current will occur when they are all in parallel.
