Answer:
Can you repost this but flip it? It’s upside down rn
Explanation:
I’m pretty sure it’s c ) meniscus . i’m not sure
Answer:
Mass released = 8.6 g
Explanation:
Given data:
Initial number of moles nitrogen= 0.950 mol
Initial volume = 25.5 L
Final mass of nitrogen released = ?
Final volume = 17.3 L
Solution:
Formula:
V₁/n₁ = V₂/n₂
25.5 L / 0.950 mol = 17.3 L/n₂
n₂ = 17.3 L× 0.950 mol/25.5 L
n₂ = 16.435 L.mol /25.5 L
n₂ = 0.644 mol
Initial mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.950 mol × 28 g/mol
Mass = 26.6 g
Final mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.644 mol × 28 g/mol
Mass = 18.0 g
Mass released = initial mass - final mass
Mass released = 26.6 g - 18.0 g
Mass released = 8.6 g
Answer:
Mass = 101891.2 g
Explanation:
Given data:
Mass of ammonia needed = ?
Mass of ammonium sulfate produced = 396 Kg = 396 ×1000 = 396000 g
Solution:
Chemical equation:
2NH₃ + H₂SO₄ → (NH₄)₂SO₄
Number of moles of (NH₄)₂SO₄:
Number of moles = mass/molar mass
Number of moles = 396000 g / 132.14 g/mol
Number of moles = 2996.8 mol
Now we will compare the moles of ammonia and ammonium sulfate
(NH₄)₂SO₄ : NH₃
1 : 2
2996.8 : 2/1×2996.8 = 5993.6 mol
Mass of ammonia needed:
Mass = number of moles × molar mass
Mass = 5993.6 mol × 17 g/mol
Mass = 101891.2 g
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