I think the answer to ur problem is 4 my hitta
<h3>
Answer:</h3>
2.41 g NaCl
<h3>
Explanation:</h3>
We are given the;
Molarity of NaCl = 0.150 M
Volume of the solution = 275.0 mL
We are required to calculate the mass of NaCl solute;
<h3>Step 1: Number of moles of NaCl solute </h3>
Moles are calculated by;
Moles = Molarity × Volume
Therefore;
Number of moles of NaCl = 0.150 M × 0.275 L
= 0.04125 moles
<h3>Step 2: Mass of NaCl solute </h3>
Mass of the compound is given by multiplying the number of moles by the molar mass of the compound.
Molar mass of NaCl = 58.44 g/mol
Therefore;
Mass of NaCl = 0.04125 moles × 58.44 g/mol
= 2.41 g
Thus, the mass of NaCl solute is 2.41 g
Answer:
4.15g
Explanation:
Balance the reaction:
2Mg + O2 = 2MgO
Find limiting reactant from the two, by dividing miles with coefficient
2.5/24.3 = 0.103 moles/2 = 0.0515
5/16 = 0.31 moles/2 = 0.156
0.0515 is small than 0.156, so limiting reactant is Mg
Compare the ratio of Mg with MgO
Ratio is 2:2
So same moles = 0.103 moles
Mass = moles x molar mass of MgO
Mass = 0.103 x 40.3
= 4.15g
*please give brainlest*
Answer:
2H₂O₂ → 2H₂O + O₂
Explanation:
H₂O₂ → H₂O + O₂
The above equation can be balance as illustrated below:
H₂O₂ → H₂O + O₂
There are 2 atoms of O on the left side and a total of 3 atoms on the right side. It can be balance by putting 2 in front of H₂O₂ and 2 in front of H₂O as shown below:
2H₂O₂ → 2H₂O + O₂
Now, the equation is balanced.
**** check ****
Element >>> Left Side >>> Right Side
H >>>>>>>>> 4 >>>>>>>>> 4
O >>>>>>>>> 4 >>>>>>>>> 4
