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Anna007 [38]
3 years ago
7

for every 10 yards on a football field there I boldly marked line labeled with the amount of yards there are two parallel sideli

nes on each side of the field if the 50 yards line is perpendicular to one of the sidelines what is its relationship to the other sideline
Chemistry
1 answer:
RUDIKE [14]3 years ago
3 0
It is perpendicular to both as the sidelines are parallel
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HELP ASAP 10 POINTS
TEA [102]

Answer:

the answer is destructive interference

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A sodium ion has a radius of 1.16 x 10^-10 m and a nearby fluoride ion has a radius of 1.9 x 10^-10 m. Determine the distance be
Ann [662]

The answer is: the distance between two nuclei is 2.35×10⁻¹⁰ m.

r(Na⁺) = 1.16×10⁻¹⁰ m; radius of sodium cation.

r(F⁻) = 1.9×10⁻¹⁰ m; radius of fluoride anion.

d(NaF) = r(Na⁺) + r(F⁻).

d(NaF) = 1.16×10⁻¹⁰ m + 1.9×10⁻¹⁰ m.

d(NaF) = 2.35×10⁻¹⁰ m; distance between two nuclei.

The sum of ionic radii of the cation and anion gives the distance between the ions in a crystal lattice.

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3 years ago
What is the best description of weathering?
zheka24 [161]
D. breakdown of rocks through mechanicals or chemicals processes
8 0
3 years ago
1Which is a dopant for a p-type semiconductor?
aalyn [17]

For a p type of semiconductor we need a dopant which is from 13th group in periodic table

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5 0
3 years ago
Read 2 more answers
An inexpensive and accurate method of measuring the quantity of electricity flowing through a circuit is to pass the current thr
Paha777 [63]

Total of 127.013 C of charge is passed

Given

 weight of Ag solution before current has passed = 1.7854 g

  weight of Ag solution after current has passed = 1.8016 g

  Molecular mass of Ag = 107.86 g

  Faraday's Constant = 96485

First of all we have to apply Faraday's First Law of Electrolysis i.e

         m = ZQ

  where

Z is propotionality constant (g/C)

Q is charge (C)

Hence,

 Z = Atomic mass of substance/ Faraday's Constant

    = \frac{107.86 g}{96485 C}

    = 0.0011178 g/C

Now ,

   change in mass before and after the passing of current (Δm)

       Δm = 1.8016g-1.7854g

             =   0.0162g

    Now  amount of coulombs passed = \frac{0.142g}{0.0011178 g/C }

          amount of coulombs passed = 127.03524 C

Thus from the above conclusion we can say that amount of coulombs have passed is 127.03524 C

Learn more about Electrolysis here: brainly.com/question/16929894

#SPJ4

7 0
2 years ago
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