Answer:
The magnitude of the velocity of glider B is 0.2m/s and the direction is the negative direction
Explanation:
Inelastic Collision
Given data
mass of glider A m1= 0.125kg
initial velocity u1=0
final velocity v1= 0.600 m/s
mass of glider B m2= 0.375kg
initial velocity u2=0
final velocity v2=?
We know that the expression for the conservation of momentum is given as
m1u1+m2u2=m1v1+m2v2
since u1=u2=u=0m/s
u(m1+m2)=m1v1+m2v2
substituting we have
0(0.125+0.0375)=0.125*0.6+0.375*v2
0=0.075+0.375v2
0.375v2=-0.075
v2=-0.075/0.375
v2=-0.2m/s
The magnitude of the velocity of glider B is 0.2m/s and the direction is the negative direction
Answer:
<h3> b. 1.18</h3>
Explanation:
The fundamental frequency in string is expressed as;
F1 = 1/2L√T/m .... 1
L is the length of the string
T is the tension
m is the mass per unit length
If the tension is increased by 40%, the new tension will be;
T2 = T + 40%T
T2 = T + 0.4T
T2 = 1.4T
The new fundamental frequency will be;
F2 = 1/2L√1.4T/m ..... 2
Divide 1 by 2;
F2/F = (1/2L√1.4T/m)/1/2L√T/m)+
F2/F = √1.4T/m ÷ √T/m
F2/F = √1.4T/√m ×√m/√T
F2/F = √1.4T/√T
F2/F = 1.18√T/√T
F2/F = 1.18
F2 = 1.18F
Hence the fundamental frequency of vibration changes by a factor of 1.18
F=ma
Therefore the net force = 1000kg × 2 metres per second per second
So F=2000 N
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The best and most correct answer among the choices provided by your question is the second choice.
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