3 years ago

A decrease in the magnitude of velocity is called

Physics

1 answer:

just olya [345]3 years ago

3 0

The answer would be energy lose

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The period (T) of an oscillating wave is 1/5s. What happens to the frequency (f) of the wave if T increases to 1/2s

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Frequency = 1/T
as the 5 is reduced, frequency is increase.
as 1 whole wave travels through a point in a lesser time now

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2 years ago

Where are the nodules of a legume found?

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Answer:

The answer is roots.

Explanation:

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As water vapor rises into the sky it gets cold. As the water cools, water vapor is transformed into liquid water. When water cha

Aleks [24]

Answer:

2: Condensation. 4: 1,d; 2,c; 3,a; 4,e;5,b.

Explanation:

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2 years ago

1) Subatomic particles called muons can be created in the upper atmosphere by collisions of cosmic rays (energetic particles com

Vsevolod [243]

Answer and explanation:

Muon travelled straight down towards the earth. Therefore the tree moves up in the rest frame of muon (option a)

In muon rest frame it travels Zero meters

Distance, d = Velocity, v * Time, s

$where, v = 0.9c = 0.9 \times 8 \times 10^8 , s = 2.2 \mu s$

$d = 0.9 \times 3 \times 10^8 \times 2.2 \times 10^{-6}\\\\d = 594m$

Distance from the top of the mountain to the tree is the same as the distance travelled by the tree in the muons rest frame

that is same as in part C which is 594m

Using lorentz contraction

In the rest frame of someone standing on the mountain

the distance is given by

$d' = \frac{d}{\gamma} = d\sqrt{1 - \frac{v^2}{c^2}}, where, \frac{1}{\gamma}= \sqrt{1 - \frac{v^2}{c^2}}$

$d' = 594\sqrt{1 - \frac{(0.9c)^2}{c^2}}$

$d' = 594\sqrt{1 - 0.81}$

$d' = 594 \times 0.4359$

d' = 258.92m

in the rest frame of someone standing on the mountain,

muon moves straight down

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3 years ago