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Flauer [41]
3 years ago
14

A 2000kg suv accelerates from rest at a rate of 3.00m/s^2. The total amount of force resisting its motion 1500N. How much force

is applied to the suvs tires by the ground to make it accelerate?
Physics
1 answer:
choli [55]3 years ago
7 0

The total force that the SUV exerts is:

F = 2000 kg * 3 m/s^2

F = 6000 N

 

Since a resisting force amounting to 1500 N is exerted, then the force exerted by the SUV tires is:

F tire = 6000 N – 1500 N

F tire = 4500 N

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You're driving your new sports car at 80 mph over the top of a hill that has a radius of curvature of 540 m. What fraction of yo
luda_lava [24]

Answer:

75.84%

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✓ the normal weight can be denoted as Wn

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Wa=apparent weight = (mg - mv^2/r)

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The apparent weightand normal weight has a ratio of

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