Speed of the beam as it passes from one transparent medium to another
let the plane is flying at some angle theta with west towards north
Now we can use the components
now since plane has to fly towards west so net speed in north must be equal to speed in south for air
So we can say
so plane has to fly in direction 14.5 degree North of west
Answer:
44.5s ; 22.64 m/s
Explanation:
The motion of the truck could be separated into 3 different phases :
First :
Time of motion :
Initial Velocity, u = 0 ; final velocity, v = 29 m/s
Acceleration, a = 2 m/s²
Recall: acceleration = change in velocity / time
Time = change in velocity / acceleration
Time = (29 - 0) / 2 = 14.5 second
Distance traveled = ((29 + 0) /2) * 14.5 = 210.25 m
Second :
Time = 25 seconds at constant speed
29 m/s for 25 seconds
v*t = 29 * 25 = 725 m
Third:
5 seconds before coming to rest
((29 + 0) /2) * 5
14.5 * 5 = 72.5 m
A.)
Length of journey = (14.5+ 25 + 5) = 44.5 seconds
B.)
Average velocity = total distance / total time taken
Average velocity = (210.25 + 725 + 72.5) / 44.5
= 1007.75 / 44.5
= 22.646067
= 22.64 m/s
The heat energy released from a piece of wire or any other section of a circuit is:
Energy = (voltage between its ends) x (current through it) x (time it's been going)
