1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Maurinko [17]
2 years ago
13

What does it mean when white light is diffracted and at a particular location the color seen is blue? Please use 2 content relat

ed sentences.
Physics
1 answer:
Brilliant_brown [7]2 years ago
3 0

When white light is diffracted and blue color is seen is due to the absorbance of wavelength of all other color except blue.

<u>Explanation: </u>

  • The white light diffracts into rainbow colors which are the 7 colors present in form of VIBGYOR.
  • VIBGYOR is the violet, Indigo, Blue, Green, Yellow, Orange and Red.
  • When the blue color is seen denotes the shortest wavelength being reflected and all other being absorbed at the specified location.

You might be interested in
For a series circuit what is the terminal voltage of a battery or power supply equal to in terms of the potential difference or
trapecia [35]

Answer: V=IR

Explanation: for a series circuit connected to a battery supply, the total emf across the circuit is given as

E = I(R + r) and by expanding, we have that E =IR + It

Where r is the internal resistance of the battery

I is the total current flowing in the circuit

R total load resistance in the circuit.

E is the total emf of the circuit.

The total emf is the sum of 2 separate voltages.

"IR" which is the terminal voltage and "Ir" which is the loss voltage.

The teenila voltage is the voltage flowing in the circuit based on the equivalent resistance of the circuit while the loss voltage is the wasted voltage based on the internal resistance of the battery source.

7 0
3 years ago
A proton having an initial velvocity of 20.0i Mm/s enters a uniform magnetic field of magnitude 0.300 T with a direction perpend
Sonja [21]

The time interval for which the proton remains in the field is -

Δt = $\frac{\pi R}{40}.

We have a proton entering a uniform magnetic field which is in a direction perpendicular to the proton's velocity.

We have to determine time interval during which the proton is in the field.

<h3>What is the magnitude of force on the charged particle moving in a uniform magnetic field?</h3>

The magnitude of force on the charged particle moving in a uniform magnetic field is given by -

F = qvB sinθ



According to the question, we have -

Entering Velocity (v) = 20 i  m/s

Magnetic field intensity (B) = 0.3 T

Leaving velocity (u) = - 20 j  m/s

Now -

The entering and leaving velocity vectors have 90 degrees difference between them. Therefore, only a quarter of distance of the complete circular path of radius 'R' is traced by the proton. Therefore -

d = $\frac{2\pi r}{4} = $\frac{\pi R}{2}

Since, the radius of circular path is not given, we will assume it R.

Therefore, time for which proton remained in the field is -

t = $\frac{\pi R}{2v} = \frac{\pi R}{40}

Hence, the time interval for which the proton remains in the field is -

Δt = $\frac{\pi R}{40}

To solve more questions on Force on charged particle, visit the link below-

brainly.com/question/14597200

#SPJ4



 



6 0
1 year ago
LAB: Thermal Engery Transfer
hodyreva [135]

Answer:

A- mass and type of material

B- type of material

C- Temperature

Explanation:

thx

6 0
2 years ago
2. Ms. McAdam, a high school principal, examines
liq [111]

Answer:

2005

Explanation:

6 0
1 year ago
An object is placed to the left of a convex mirror, such that the object-to-image distance is 140 cm.
labwork [276]

Answer:

The focal length of the mirror is 52.5 cm.

Explanation:

Given that,

Object to Image distance d = 140 cm

Image distance v= 35 cm

We need to calculate the object distance

u = d-v

u = 140-35=105\ cm

We need to calculate the focal length

Using formula of mirror

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}

Put the value into the formula

\dfrac{1}{f}=\dfrac{1}{-105}+\dfrac{1}{35}

\dfrac{1}{f}=\dfrac{2}{105}

f=52.5\ cm

Hence, The focal length of the mirror is 52.5 cm.

6 0
3 years ago
Other questions:
  • An object, initially at rest, is subject to an acceleration of 34 m/s2. how long will it take for that object to travel 3400 m?
    15·1 answer
  • Write equations for both the electric and magnetic fields for an electromagnetic wave in the red part of the visible spectrum th
    14·1 answer
  • A 10 m long high tension power line carries a current of 20 A perpendicular to Earth's magnetic field of 5.5 x10⁻⁵ T. What is th
    12·1 answer
  • When does a object exerts an action force
    12·1 answer
  • What is the term for the ability to cause change in matter?
    6·1 answer
  • A force is a push or pull.<br> O<br> A. True<br> O<br> B. False
    14·2 answers
  • According to the law of conservation of energy, how are potential energy and kinetic energy related?
    6·1 answer
  • Based on the images, what conclusion can Mariam make about fish and mammals?
    5·1 answer
  • A meteor is falling towards the earth. The mass and the radius of the earth is 6×10^24 kg and 6.4×10^3 km respectively. What is
    5·1 answer
  • If the loop the car is currently on has a radius of 26.0 m , find the minimum height h so that the car will not fall off the tra
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!