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scoray [572]
3 years ago
13

You have two lightweight metal spheres, each hanging from an insulating nylon thread. One of the spheres has a net negative char

ge, while the other sphere has no net charge.
(a) If the spheres are close together but do not touch, will they
(i) attract each other,
(ii) repel each other, or
(iii) exert no force on each other
Physics
1 answer:
kkurt [141]3 years ago
8 0

Answer:attract each other

Explanation:

When two-sphere, one with a negative charge and another neutral is brought close together but do not touch then they try to attract each other.

This because of the polarization of the neutral sphere as it is placed in the vicinity of a negatively charged sphere. The negatively charged sphere will induce the positive charge in the neutral sphere and they will attract each other according to Columb law.

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yKpoI14uk [10]

The net force applied to the object equals the mass of the object multiplied by the amount of its acceleration." The net force acting on the soccer ball is equal to the mass of the soccer ball multiplied by its change in velocity each second (its acceleration).

8 0
3 years ago
Which of the following statements about iron filings placed upon glass resting on top of a bar magnet is false?
leva [86]

The answer would be D. Because the iron fillings are attracted to the magnet underneath the glass.

5 0
3 years ago
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A dragster starts from rest and travels 1/4 mi in 6.80 s with constant acceleration. What is its velocity when it crosses the fi
Ahat [919]
<h2>Its velocity when it crosses the finish line is 117.65 m/s</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = ?

        Time, t = 6.8 s    

        Displacement, s = 1/4 mi =    400 meters

     Substituting

                      s = ut + 0.5 at²

                      400 = 0 x 6.8 + 0.5 x a x 6.8²

                      a = 17.30 m/s²

Now we have equation of motion v = u + at

     Initial velocity, u = 0 m/s

     Final velocity, v = ?

     Time, t = 6.8 s

      Acceleration, a = 17.30 m/s²

     Substituting

                      v = u + at  

                      v = 0 + 17.30 x 6.8

                      v = 117.65 m/s

Its velocity when it crosses the finish line is 117.65 m/s

6 0
3 years ago
A force of 900 N is applied to a 9kg object. How fast will it accelerate?
saul85 [17]

Answer:  15 m/s2

Explanation: I hope this helps or right because I learned this a few months ago

7 0
2 years ago
Read 2 more answers
Part 1 of 2
Readme [11.4K]

Answer:

I got you.. i'm in middle school and had that same question.

Explanation:

Refer to the diagram shown below.

The vertical distance traveled is

s = 25 m

The initial vertical launch velocity is zero.

Therefore

s = (1/2)*g*t²

where g = 9.8 m/s²

t = the time of flight, s

That is,

0.5*9.8*t² = 25

t² = 25/4.9 = 5.102

t = 2.26 s

Answer: 2.26 s

3 0
3 years ago
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