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3 years ago

PLEASE HELP, I’ll give u Brainiest!!!

Mathematics

1 answer:

Slav-nsk [51]3 years ago

6 0

Answer:

u subtract from 180 each

Step-by-step explanation:

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What is the variable in the expression 2X - 25

SpyIntel [72]

The variable is x.

Hope that helps :)

8 0

1 year ago

What is the geometric mean of 3 and 15

Helen [10]

Trick question. There is not one. Due to the fact that 3 is a factor of 15 and if you factor it you will get five which is a third of 15.

4 0

3 years ago

The weight of an object on Earth varies directly as the weight of the same object on the moon. A 300 pound object on Earth would

slava [35]

Answer: 12 pounds.

Step-by-step explanation:

To solve this question, we'll use the direct proportion which is.

y = kx

Where,

y = weight on moon = 48 pounds

x = weight on Earth = 300 pounds

k = Unknown

y = kx

48 = 300k

k = 48/300

k = 0.16

The weight that a 75 pound object on Earth would weigh on the moon will be:

y = kx

where,

y = weight on moon = Unknown

k = 0.16

x = weight on Earth = 75 pounds

y = kx

y= 0.16 × 75

y = 12 pounds

The weight on the moon will be 12 pounds.

7 0

2 years ago

Dy/dx = 2xy^2 and y(-1) = 2 find y(2)

Anarel [89]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2887301

—————

Solve the initial value problem:

dy
——— = 2xy², y = 2, when x = – 1.
dx

Separate the variables in the equation above:

$\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}$

Integrate both sides:

$\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}$

$\mathsf{\dfrac{1}{y}=-(x^2+C_1)}$

Take the reciprocal of both sides, and then you have

$\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}$

In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:

y = 2, when x = – 1. So,

$\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}$

$\mathsf{C_1=-\,\dfrac{3}{2}}$

Substitute that for C₁ into (i), and you have

$\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}$

So y(– 2) is

$\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>

7 0

2 years ago

Figure out this missing number pattern:\<br> 1,1,2,3,5_,_,_

Mamont248 [21]

What you have here is the fibonacci sequence.
Each number in the sequence adds itself to the number before it.
1+1 = 2
1+2 = 3
3+2 = 5
5+3 = 8
8+5 = 13
the sequence is 0,1,1,2,3,5,8,13

8 0

2 years ago