Answer:
The order of the production of bacteria is 1.
12,787 bacteria will be present after 112 min.
is the rate constant for the process.
Explanation:
Rate of formation of bacteria when there 100 bacteria: R
Rate of formation of bacteria when there 200 bacteria: R' =2R
Rate of formation of bacteria is directly proportional to the number of bacteria:
![\frac{R}{R'}=\frac{k[200]^x}{k[400]^x}](https://tex.z-dn.net/?f=%5Cfrac%7BR%7D%7BR%27%7D%3D%5Cfrac%7Bk%5B200%5D%5Ex%7D%7Bk%5B400%5D%5Ex%7D)

x = 1
The order of the production of bacteria is 1.
The half life of the process = 
Rate constant of the process = k
For first order process k is only dependent on half life:


For the first order process the increment numbers is given ;

Where:
= Initial population
N = Population after time t.
We have ;

t = 112 minutes


12,787 bacteria will be present after 112 min.
is the rate constant for the process.