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aleksandr82 [10.1K]
4 years ago
11

Density is given in ____. a. Pa/cm3 c. g/s2 b. N/m2 d. g/cm3 Please select the best answer from the choices provided A B C D

Chemistry
2 answers:
Ray Of Light [21]4 years ago
7 0
Density is given in Mass/Volume so the answer is D
serg [7]4 years ago
7 0
Indeed Density (d) is in fact given in
g \div {cm}^{3}
Answer [D].

Since density (d) is a measurement of a substance's mass per volume, or d = m/v, we can see that units would be in g, kg, etc for mass and mL, L, etc for volume. And then where does
{cm}^{3}
come from?? Well 1 mL of water occupies a cylindrical space of 1 cubic cm.
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What is a spectator ion?
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<span>A spectator ion is an ion that exists in the same form on both the reactant and product sides of a chemical reaction.</span>
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determine mass of water formed when 12.5 L NH3(at298K and 1.50atm) is reacted with 18.9L of O2 (at 323K and 1.1atm)
sasho [114]

The  mass  of water formed  is


<u><em>calculation</em></u>

Use  the  ideal   gas  equation   to  calculate the  moles of  NH3  and O2

that  is  Pv= n RT

where;  P= pressure,  

V=  volume,

n = number  of  moles,

R=gas   constant  = 0.0821  l .atm/ mol.K

make n the formula of  the subject  by diving   both side  by  RT

n =  PV /RT

The   moles of NH3

n= (1.50 atm  x 12.5 L) /(  0.0821 L. atm /mol.k   x 298 K)  =0.766  moles

The  moles  of  O2

=(1.1 atm  x 18.9  L) /  (  0.0821 L. atm/ mol.k   x 323 K) = 0.784  moles


write the reaction  between  NH3  and  O2

4 NH3  + 5 O2  →4 No  +6H2O


from  equation above  0.766  moles of NH3  reacted to produce  

0.766 x 6/4 =1.149 moles of H2O


0.784  moles of O2   reacted to  produce  0.784  x 6/5=0.9408  moles  of H20


since  O2  is totally  consumed, O2  is the limiting  reagent  and therefore  the  moles of H2O  produced=  0.9408  moles


mass  of  H2O  = moles x molar mass

 from  periodic table the  molar mass  of H2O  =  (1 x2)+16= 18  g/mol

mass = 18 g/mol  x 0.9408  moles= 16.93  grams


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3 years ago
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1.00

Explanation:

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