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Anna11 [10]
3 years ago
8

Name three of the most sensitive parts of your body (Appropriate parts. Ex: finger, wrist, shoulder, etc.)

Chemistry
1 answer:
yKpoI14uk [10]3 years ago
3 0
Inner thigh, eyes, brain
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If 5.00 mL of 1.00 M HCl is used to titrate the hydroxide ion produced by a piece of Sodium, What mass of Sodium is used in gram
suter [353]

Answer:

Explanation:

Equation of the reaction:

NaOH + HCl --> NaCl + H2O

Volume of HCl = 5 ml

Molar concentration = 1 M

Number of moles = molar concentration * volume

= 1 * 0.005

= 0.005 mol of HCl

By stoichiometry, 1 mole of HCl completely neutralizes 1 mole of NaOH

Therefore, number of moles of NaOH = 0.005 mol

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

NaOH --> Na+ + OH-

Mass = molar mass * number of moles

= 40 * 0.005

= 0.2 g of Na+

6 0
3 years ago
Balancing chemical equations
mojhsa [17]

<span>2H2 + O2 → 2H2O</span>

<span>
</span>

<span>okay???</span>

<span>
</span>

4 0
4 years ago
) determine the henry's law constant for ammonia in water at 25°c if an ammonia pressure of 0.022 atm produces a solution with a
Nataly [62]

Answer:

a. 59 m/atm

Explanation:

  • To solve this problem, we must mention Henry's law.
  • <em>Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.</em>
  • It can be expressed as: C = KP,

C is the concentration of the solution (C = 1.3 M).

P is the partial pressure of the gas above the solution (P = 0.022 atm).

K is the Henry's law constant (K = ??? M/atm),

∵ C = KP.

∴ K = C/P = (1.3 M)/(0.022 atm) = 59.0 M/atm.

3 0
3 years ago
A basketball weighs approximately 1.35 kg. What is this mass in grams (g)?<br><br> step by step
choli [55]

Answer:

1350 g

Explanation: just add a 0

8 0
3 years ago
A sample of metal has a mass of 16.5916.59 g, and a volume of 5.815.81 mL. What is the density of this metal
Oxana [17]

Answer:

=> 2.8554 g/mL

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m)     = 16.59 g

Volume (v) =  5.81 mL

From our question, we are to determine the density (rho) of the rock.

The formula:

p = \frac{m}{v}

Substitute the values into the formula:

​p = \frac{16.59 g}{5.81 mL} \\   = 2.8554 g/mL

= 2.8554 g/mL

Therefore, the density (rho) of the rock is 2.8554 g/mL.

5 0
2 years ago
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