Question

The rate constant for the first-order decomposition of n2o is 3.40 s-1. what is the half-life of the decomposition?

Answer 1

Answer: The half life of the decomposition reaction is 0.204 s

Explanation:

The equation used to calculate half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

k = rate constant of the reaction = $3.40s^{-1}$

$t_{1/2}$ = half life of the reaction = ?

Putting values in above equation, we get:

$t_{1/2}=\frac{0.693}{3.40s^{-1}}\\\\t_{1/2}=0.204s$

Hence, the half life of the decomposition reaction is 0.204 s

Answer 2

Hey There:

First order  half life equation :

T 1/2  = ln ( 2 ) /K

T 1/2 = 0.693 / 3.40

T 1/2 = 0.204 s

Answer B