Question

BRAINLIEST

Answer 1

Answer:

The correct answer is 6.31 M

Explanation:

The molecular weight (MM) of NaOH is calculated as follows:

MM(NaOH) = Molar mass Na + Molar mass O + Molar mass H

                   = 23 g/mol + 16 g/mol + 1 g/mol

                   = 40 g/mol

We need the MM to convert from grams to moles. The molarity (moles of solute per liter of solution, in mol/L) can be calculated by dividing the mass into the volume in liters (195 ml = 0.195 L) and then multiplying by the MM as follows:

M = 49.24 g/0.195 L x 1 mol/40 g = 6.31 mol/L = 6.31 M

Answer 2

Answer:

M = 6.31 M

Explanation:

Data:

mass = 49.24 g of NaOH

solution volume = 195 mL = 0.195 L

MW NaOH = 39.99 g/mol

M = ?

The equation to calculate the molarity of a solution is as follows:

$M=\frac{moles}{solution volume}$

To calculate the moles of NaOH the following equation is used:

$MW=\frac{mass}{mol}$

Where MW is the molecular weight of NaOH, now we must clear the moles from the previous equation.

$mol=\frac{mass}{MW}$

$mol=\frac{49.24g}{39.99\frac{g}{mol} }=1.23 mol$

We place the moles and the volume of the solution in the molarity equation

$M=\frac{1.23mol}{0.195L} =6.31 M$