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amid [387]
3 years ago
14

BRAINLIEST

Chemistry
2 answers:
NikAS [45]3 years ago
5 0

Answer:

The correct answer is 6.31 M

Explanation:

The molecular weight (MM) of NaOH is calculated as follows:

MM(NaOH) = Molar mass Na + Molar mass O + Molar mass H

                   = 23 g/mol + 16 g/mol + 1 g/mol

                   = 40 g/mol

We need the MM to convert from grams to moles. The molarity (moles of solute per liter of solution, in mol/L) can be calculated by dividing the mass into the volume in liters (195 ml = 0.195 L) and then multiplying by the MM as follows:

M = 49.24 g/0.195 L x 1 mol/40 g = 6.31 mol/L = 6.31 M

Bad White [126]3 years ago
3 0

Answer:

M = 6.31 M

Explanation:

<u>Data:</u>

mass = 49.24 g of NaOH

solution volume = 195 mL = 0.195 L

MW NaOH = 39.99 g/mol

M = ?

The equation to calculate the molarity of a solution is as follows:

M=\frac{moles}{solution volume}

To calculate the moles of NaOH the following equation is used:

MW=\frac{mass}{mol}

Where MW is the molecular weight of NaOH, now we must clear the moles from the previous equation.

mol=\frac{mass}{MW}

mol=\frac{49.24g}{39.99\frac{g}{mol} }=1.23 mol

We place the moles and the volume of the solution in the molarity equation

M=\frac{1.23mol}{0.195L} =6.31 M

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5 0
3 years ago
Which substance can not be broken down by a
Tomtit [17]

Answer:  (3) silicon

Explanation:

Element is a pure substance which is composed of atoms of similar elements.It can not be decomposed into simpler constituents using chemical reactions.Example: Silicon (Si)

Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.It can be decomposed into simpler constituents using chemical reactions. Example: ethane (C_2H_6), propanone (CH_3COCH_3) and water (H_2O)

7 0
3 years ago
Pure ethylene glycol, , is added to 2.00 kg of water in the cooling system of a car. The vapor pressure of the water in the syst
spayn [35]

Answer:

1367.7 g of ethylene glycol was added to the solution

Explanation:

In order to find out the mass of glycol we added, we apply the colligative property of lowering vapor pressure: ΔP = P° . Xm

ΔP = Vapor pressure of pure solvent (P°) - Vapor pressure of solution(P')

525.8 mmHg - 451 mmHg = 451 mmHg . Xm

74.8 mmHg / 451 mmHg = Xm → 0.166 (mole fraction of solute)

Xm = Mole fraction of solute / Moles of solute + Moles of solvent

We can determine the moles of solvent → 2000 g . 1  mol/18 g = 111.1 mol

(Notice we converted the 2kg of water to g)

0.166 = Moles of solute / Moles of solute + 111.1 moles of solvent

0.166 (Moles of solute + 111.1 moles of solvent) = Moles of solute

18.4 moles = Moles of solute - 0.166 moles of solute

18.4 = 0.834 moles of solute → Moles of solute = 18.4/0.834 = 22.06 moles

Let's convert the moles to mass → 62 g/mol . 22.06 mol = 1367.7 g

6 0
3 years ago
One mole of acetyl chloride was mixed with one mole of dimethylamine. After the reaction is complete, what species can be found
fredd [130]

Answer:

N,N-dimethylacetamide is formed.

Explanation:

  • It is an example of a nucleophilic addition-elimination reaction. Here dimethylamine acts as a nucleophile.
  • In the first step, dimethyl amine gives nucleophilic addition reaction at carbonyl center of acetyl chloride.
  • In the second step, removal of Cl atoms occurs.
  • In the third step, deprotonation takes place from amino group to produce N,N-dimethylacetamide.
  • Full reaction mechanism has been shown below.

7 0
3 years ago
Zn-64 = 48.63%
sladkih [1.3K]

Answer:

A = 65.46 u

Explanation:

Given that,

The composition of zinc is as follows :

Zn-64 = 48.63%

Zn-66 = 27.90%

Zn-67 = 4.10%

Zn-68 = 18.75%

Zn-70 = .62%

We need to find the  average atomic mass of the given element. It can be solved as follows :

A=\dfrac{48.63\times 64+27.90\times 66+4.1\times 67+18.75\times 68+0.62\times 70}{100}\\A=65.46\ u

So, the average atomic mass of zinc is 65.46 u.

6 0
2 years ago
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