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N76 [4]
2 years ago
15

Order these numbers from least to greatest.

Mathematics
1 answer:
Harlamova29_29 [7]2 years ago
5 0
-867, -145, -12.1, 12110
Note that a negative number converts a number to a very small number..
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For a button to fit through its button-hole the hole needs to be the size of the buttons diameter what size buttonhole is needed
Lena [83]

Answer:the size of the button hole is 2.35 cm

Step-by-step explanation:

For a button to fit through its button-hole, the hole needs to be the size of the buttons diameter.

The formula for determining the circumference of a circle is expressed as

Circumference = πd or 2πr

Where

d represents the diameter of the circle

π is a constant given as 3.14

From the information given, the circumference of the button is 7.38 cm. Therefore, the diameter of the button will be

d = circumference/π = 7.38/3.14

d = 2.35 cm

3 0
3 years ago
Help me Please....................
MakcuM [25]

9514 1404 393

Answer:

  1.3363

Step-by-step explanation:

The basic idea here is to find an expression for the direction vector between a point on L1 and a point on L2. Then, solve for the points on L1 and L2 that make that vector perpendicular to both lines L1 and L2. (The dot product of direction vectors is zero.) The distance between the points found is the shortest distance between the lines.

__

Let P be a point on L1. Then the parametric equation for P is ...

  P = (6t, 0, -t) . . . . . . origin + t × direction vector

Let Q be a point on L2. The direction vector for L2 is given by the difference between the given points. It is (4-1, 1-(-1), 6-1) = (3, 2, 5). Then the parametric equation for Q is ...

  Q = (3s+1, 2s-1, 5s+1) . . . . (1, -1, 1) + s × direction vector

The direction vector for PQ is ...

  Q -P = (3s+1-6t, 2s-1, 5s+1+t)

The dot product of this and the two lines' direction vectors will be zero:

  (3s+1-6t, 2s-1, 5s+1+t)·(6, 0, -1) = 0 = 13s -37t +5 . . . perpendicular to L1

  (3s+1-6t, 2s-1, 5s+1+t)·(3, 2, 5) = 0 = 38s -13t +6 . . . perpendicular to L2

The solution to these equations is ...

  s = -157/1237

  t = 112/1237

Then (Q-P) becomes (94, -1551, 564)/1237, and its length is ...

  |PQ| = √(94² +1551² +564²)/1237 ≈ 1.3363

The distance between the two lines is about 1.3363 units.

8 0
3 years ago
Which expression is equivalent to (x^6y^8)^3 / x^2y^2?​
stiks02 [169]

Answer:

=x^16y^26

Step-by-step explanation:

x^18y^24xy^2

x^16y^24xy^2

8 0
2 years ago
Convert 12 1/2% to a simplified fraction.
Scorpion4ik [409]
The answer is 1/8, hope this helps you :)
5 0
2 years ago
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Diameter of a circle is two units. What is the radius of the circle?
bonufazy [111]
Answer is 3.5 feet enjoy
5 0
2 years ago
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