Answer: t = 5
Step-by-step explanation: step one cross multiply 4/t = 2/2.5
(4) * (2.5) = 2 * t so 10 = 2t / step two flip the equation 2t = 10
step three divide both sides by two 2t/2 = 10/2 t = 5
Yes he can because if you multiply 3x2 and 3x5 and find the sum which is 6 and 15 find TLCM you get 30 so yes
7v-5v=18
2v=18
v=9
hope this helps!
<span>If set X is made up of the possible ways five students, represented by A, B, C, D, and E, can be formed into groups of three, then the set X consists of such triples {ABC, ABD, ABE, ACD, ACE, ADE, BCD, BCE, BDE, CDE} (note that triple ABC is the same as triple ACB, or BCA, or BAC, or CAB, or CBA). The set X totally contains 10 elements (triples). The first statement is true.
</span>
<span>If set
Y is made up of the possible ways five students can be formed into
groups of three if student A must be in all possible groups, then </span><span>the set Y consists of such triples {ABC, ABD, ABE, ACD, ACE, ADE} and contains 6 elements. The second statement is also true.
</span>
<span>If person E must be in each group, then there can be only one group is false statement, because you can see from the set X that triples which contains E are 6.
</span>
<span>There are three ways to form a group if persons A and C must be in it. This statement is true and these groups are ABC, ACD, ACE.</span>
Answer:
204/2=102
Step-by-step explanation:
