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Sati [7]
3 years ago
15

Eleanor paid an annual premium of $2,000 in total coverage for her homeowner's insurance, including $250,000 in damage coverage

and $250,000 in liability coverage. Six years into her policy, a tree fell on Eleanor's home and caused $40,000 worth of damage. Eleanor's insurance company paid the claim. Did the cost of the benefit of transferring the risk to the insurance company outweigh the cost of the premium? (5 points)
Business
1 answer:
erastovalidia [21]3 years ago
3 0

Answer:

Yes, the benefit of transferring the risk to the insurance company did outweigh the cost of paying insurance premiums.

During six years Eleanor paid $2,000 per year in insurance premium, totaling $12,000. After the tree damaged Eleanor's house, the cost of the repairs was $40,000, which is much higher than $12,000.

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Suppose you had to test how well two types of soap work. describe your experiment by using terms control and variable.
Vinil7 [7]

In testing the soap with the use of  control and variable, you need to differentiate both of the soaps that is needed to be differentiated with having to name the materials used and the soaps that are under the control and under the variable. The control will be the materials needed as it is the one responsible of changing the variable as the soaps are the variable because they will likely change as the experiment is conducted.

6 0
3 years ago
25)
boyakko [2]

Answer:

B

Explanation:

8 0
3 years ago
Grouping workers according to their similar skills, resource use, and expertise is called a _______ structure.
Semenov [28]
Not sure about this answer I will think about it
6 0
4 years ago
The Carbondale Hospital is considering the purchase of a new ambulance. The decision will rest partly on the anticipated mileage
Shtirlitz [24]

Answer:

a. Year 6 Forecast = 3,775

b. Mean Absolute Deviation (MAD) = 108.3

c. Year 6 Forecast = 3,780

Explanation:

Given

The miles driven during the past 5 years are as​ follows

Year 1 -- 3,100

Year 2 --- 4,050

Year 3 --- 3,450

Year 4 ---- 3,750

Year 5 --- 3,800

a. The forecast for year 6 is calculated as follows;

Using a 2 year moving average

Forecast = ½(Year 4 + Year 5)

Forecast = ½(3750 + 3800)

Forecast = ½ * 7550

Forecast = 3,775

b. Calculating the Mean Absolute Deviation (MAD), if two years moving average is used.

------------------------------2 year difference ----- Difference

Year 1 -- 3,100 ------------------------------------------

Year 2 --- 4,050 -----------------------------------------

Year 3 --- 3,450 ---- 3,575 -------- 125

Year 4 ---- 3,750 ---- 3,750 ------ 0

Year 5 --- 3,800 ----- 3,600 ------ 200

The 2-year difference column is calculated using.

Summation of previous 2 years forecast * ½

Year 1 and 2 are empty because they don't have previous 2 years.

For year 3;

2 year difference = ½ (year 1 + year 2)

= ½(3,100 + 4,050)

= ½ (7,150)

= 3,575

For year 4

2 year difference = ½ (year 2 + year 3)

= ½(4,050 + 3,750)

= ½ (7,500)

= 3,750

For year 5:

2 year difference = ½ (year 3 + year 4)

= ½(3,750 + 3,450)

= ½ (7,200)

= 3,600

Mean Absolute Deviation (MAD) = (Summation of Difference)/3

Mean Absolute Deviation (MAD) = (125 + 0 + 200)

Mean Absolute Deviation (MAD) = 325/3

Mean Absolute Deviation (MAD) = 108.3

c. for year 6 using a weighted​ 2-year moving average with weights of 0.40 and 0.60

For year 5:

Forecast = 0.4 * year 4 + 0.6 * year 5

= 0.4(3,750) + 0.6(3,800)

= 3,780

5 0
4 years ago
My answer b am I right
pychu [463]
Yes, you are correct :)
5 0
3 years ago
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