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Natali [406]
3 years ago
14

If the child pulls with a force of 20 N for 12.0 m , and the handle of the wagon is inclined at an angle of 25 ∘ above the horiz

ontal, how much work does the child do on the wagon?
Physics
1 answer:
lilavasa [31]3 years ago
4 0

Answer: 217.52 N

Explanation: The applied force is 20 N, the distance covered is 12.0 m and the angle is 25° above the horizontal.

Hence the formulae that defines work done is given by

W = Force × distance

But since the force has been inclined at an angle θ above the horizontal, the horizontal component of force is neccesary to produce the required motion to make the child do work on the wagon.

Hence

Work done = (horizontal component of force) × distance

Work done = F cos θ × distance

Work done = 20 cos 25 × 12 = 217.52 N

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When the starter motor on a car is engaged, there is a 290 A current in the wires between the battery and the motor. Suppose the
Tema [17]

Answer:

33.6\times10^{-4}}\text{ m} = 3.36 mm

Explanation:

From Ohm's law,

V = IR (Voltage = Current * Resistance)

R = \dfrac{V}{I}

The geometric definition of resistance is

R = \rho\dfrac{l}{A}

where \rho is the resistivity of the material, l  and A are the length and cross-sectional area, respectively.

A = \rho\dfrac{l}{R}

A = \rho\dfrac{l\timesI}{V}

Since the wire is assumed to have a circular cross-section, its area is given by

A = \pi\dfrac{d^2}{4} where d is the diameter.

\pi\dfrac{d^2}{4} = \rho\dfrac{l\timesI}{V}

d = \sqrt{\dfrac{4\rho l I}{\pi\times V}}

Resistivity of copper = 1.68\times10^{-8}. With these and other given values,

d = \sqrt{\dfrac{4\times1.68\times10^{-8}\times1.5\times290}{3.14\times 0.55}}

d = \sqrt{1128.43\times10^{-8}}

d = 33.6\times10^{-4} \text{ m}

5 0
3 years ago
Two basketballs of equal mass are rolling toward each other at constant velocities. The first basketball (B1) has a velocity of
slamgirl [31]

v'_2 = \frac{2m_1}{m_1+m_2} (4.3) - \frac{m_1-m_2}{m_1+m_2} (4.3)\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} (4.3) + \frac{2m_2}{m_1+m_2} (4.3)

<u>Explanation:</u>

Velocity of B₁ = 4.3m/s

Velocity of B₂ = -4.3m/s

For perfectly elastic collision:, momentum is conserved

m_1v_1 + m_2v_2 = m_1v'_1 + m_2v'_2

where,

m₁ = mass of Ball 1

m₂ = mass of Ball 2

v₁ = initial velocity of Ball 1

v₂ = initial velocity of ball 2

v'₁ = final velocity of ball 1

v'₂ = final velocity of ball 2

The final velocity of the balls after head on elastic collision would be

v'_2 = \frac{2m_1}{m_1+m_2} v_1 - \frac{m_1-m_2}{m_1+m_2} v_2\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} v_1 + \frac{2m_2}{m_1+m_2} v_2

Substituting the velocities in the equation

v'_2 = \frac{2m_1}{m_1+m_2} (4.3) - \frac{m_1-m_2}{m_1+m_2} (4.3)\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} (4.3) + \frac{2m_2}{m_1+m_2} (4.3)

If the masses of the ball is known then substitute the value in the above equation to get the final velocity of the ball.

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3 years ago
Can you walk on the moon
morpeh [17]
You can. But the gravity on the moon is 1/6th the gravity on Earth. This means 300 lbs man would only weigh 50 lbs. 
7 0
3 years ago
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Why is temperature scalar?
shepuryov [24]
Temperature is just a measure of how HOT or COLD a substance is, which can be easily defined by a magnitude using a numerical value say “300 K” or “27°C”. Hence we can say it is a scalar quantity.

But the energy which transfer by virtue of a temperature difference is a vector quantity, as it has both magnitude and direction of motion (from High temperature to low temperature region).
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3 years ago
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Svetllana [295]

Answer:

2 kg

Explanation:

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mass = force / acceleration

mass = 10 / 5

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3 years ago
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