What is the solution of the equation below?x/6=x-4/2
2 answers:
You might be interested in
Answer:
S(-2, -3)
Step-by-step explanation:
Find the diagram attached below,=. Frim the diagram, the coordinate of R and T are (-5, 3) and (-1, -5) respectively. If the ratio of RS to ST is 3:1, the coordinate of S can be gotten using the midpoint segment formula as shown;
S(X, Y) = {(ax1+bx2/a+b), (ay1+by1/a+b)} where;
x1 = -5, y1 = 3, x2 = -1, y2 = -5, a = 3 and b =1
Substitute the values into the formula;
X = ax2+bx1/a+b
X = 3(-1)+1(-5)/3+1
X = -3-5/4
X = -8/4
X = -2
Similarly;
Y = ay2+by1/a+b
Y = 3(-5)+1(3)/3+1
Y = -15+3/4
Y = -12/4
Y = -3
Hence the coordinate of the point (X, Y) is (-2, -3)
Answer:
c) 6x + y = -52 is required equation perpendicular to the given equation.
Step-by-step explanation:
If the equation is of the form : y = mx + C.
Here m = slope of the equation.
Two equations are said to be perpendicular if the product of their respective slopes is -1.
Here, equation 1 : -x + 6y = -12
or, 6y = -12 + x
or, y = (x/6) - 2
⇒Slope of line 1 = (1/6)
Now, for equation 2 to be perpendicular:
Check for each equation:
a. x + 6y = -67 ⇒ 6y = -67 - x
or, y = (-x/6) - (67/6) ⇒Slope of line 2 = (-1/6)
but
b. x - 6y = -52 ⇒ -6y = -52 - x
or, y = (x/6) + (52/6) ⇒Slope of line 2 = (1/6)
but
c. 6x + y = -52
or, y =y = -52 - 6x ⇒Slope of line 2 = (-6)
Hence, 6x + y = -52 is required equation 2.
d. 6x - y = 52 ⇒ -y = 52 - 6x
or, y = 6x - 52 ⇒Slope of line 2 = (6)
but
Hence, 6x + y = -52 is the only required equation .