Answer:
B: T = ½R
Step-by-step explanation:
From the given graph, we see the following;
When T = 2, R = 4
When T = 3, R = 6
When T = 4, R = 8
When T = 5, R = 10
Looking at those values, we can see a pattern where R is always equal to 2T.
Or T = ½R
Thus, option B is the answer.
Answer:
Part c) ![V=16,500\ m^3](https://tex.z-dn.net/?f=V%3D16%2C500%5C%20m%5E3)
Part d)
or ![V=292,999.68\ mm^3](https://tex.z-dn.net/?f=V%3D292%2C999.68%5C%20mm%5E3)
Step-by-step explanation:
Part c) Find the volume of the inverted rectangular pyramid
The volume of the rectangular pyramid is equal to
![V=\frac{1}{3}Bh](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7DBh)
where
B is the area of the rectangular base
h is the height of pyramid
<em>Find the area of the base B</em>
![B=(60)(15)=900\ m^2](https://tex.z-dn.net/?f=B%3D%2860%29%2815%29%3D900%5C%20m%5E2)
![h=55\ m](https://tex.z-dn.net/?f=h%3D55%5C%20m)
substitute
![V=\frac{1}{3}(900)(55)](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%28900%29%2855%29)
![V=16,500\ m^3](https://tex.z-dn.net/?f=V%3D16%2C500%5C%20m%5E3)
Part d) Find the maximum volume of tea in the tea cup
we know that
The volume of cylinder (tea cup) is equal to
![V=\pi r^{2}h](https://tex.z-dn.net/?f=V%3D%5Cpi%20r%5E%7B2%7Dh)
we have
![r=36\ mm\\h=72\ mm](https://tex.z-dn.net/?f=r%3D36%5C%20mm%5C%5Ch%3D72%5C%20mm)
substitute
![V=\pi (36)^{2}(72)](https://tex.z-dn.net/?f=V%3D%5Cpi%20%2836%29%5E%7B2%7D%2872%29)
-----> exact value
<em>Find the approximate value</em>
assume
![\pi =3.14](https://tex.z-dn.net/?f=%5Cpi%20%3D3.14)
![V=93,312(3.14)=292,999.68\ mm^3](https://tex.z-dn.net/?f=V%3D93%2C312%283.14%29%3D292%2C999.68%5C%20mm%5E3)
12y = 132
Now, solve for y.
Do the inverse operation.
12y = 132
12y/12 = 132/12
y= 132/12
y= 11
Equation: 12y = 132
Y equals: 11
Well u add up the surface are of all the numbers showed then, You multiply the nuber u got (or 48) times two. So the answer is 96 cm3