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3 years ago

Which statement is correct?

Mathematics

2 answers:

natima [27]3 years ago

6 0

Answer:

A line that rises from left to right has a positive slope

Step-by-step explanation:

Verify each statement

case A) A horizontal line has no slope

The statement is False

Because a horizontal line has a slope equal to zero

case B) A vertical line has a slope of zero

The statement is False

Because a vertical line has a undefined slope

case C) A line that rises from left to right has a positive slope

The statement is True

case D) A line that falls right to left has a negative slope

The statement is False

Because a is a positive slope

skelet666 [1.2K]3 years ago

5 0

A line that rises from left to right has a positive slope

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The points (-5,r) and (-2,15) lie on a line with a slope of 3. Find the missing coordinate r. <br> .

Komok [63]

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3 years ago

There are 70 students in the school band. 40% of them are sixth graders, 20% are seventh graders, and the rest are eighth grader

8090 [49]

Answer:

40%

Step-by-step explanation:

40% of 70 is 28

20% of 70 is 14

so there are 28 8th graders 28 is 40% of 70

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3 years ago

Read 2 more answers

If CDE ~ GDF, find ED

qaws [65]

Answer:

Step-by-step explanation:

$\triangle CDE \sim \triangle GDF.. (given) \\\\\therefore \frac{CD}{GD} =\frac{DE}{DF}.. (csst) \\\\\therefore \frac{15}{x+3} =\frac{3x+1}{4}\\\\ \therefore \: 15 \times 4 = (x + 3)(3x + 1) \\ \\ \therefore \: 60 = 3 {x}^{2} + x + 9x + 3 \\ \\ \therefore 3 {x}^{2} + 10x + 3 - 60 = 0 \\ \therefore 3 {x}^{2} + 10x - 57 = 0 \\ \therefore 3 {x}^{2} + 19x - 9x - 57 = 0 \\ \therefore \: x(3x + 19) - 3(3x + 19) = 0 \\\therefore \: (3x + 19)(x - 3) = 0 \\ \therefore \: 3x + 19 = 0 \: \: or \: \: x - 3 = 0 \\ \therefore \: x = - \frac{19}{3} \: \: or \: \: x = 3 \\ \because \: x \: can \: not \: be \: - ve \\ \therefore \: x = 3 \\ ED = 3x + 1 = 3 \times 3 + 1 \\ \huge \red{ \boxed{ ED= 10}}$

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3 years ago

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Nikolay [14]

Answer:

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3 years ago

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A hair salon completed a survey of 367 customers about satisfaction with service(Dissatisfied, Neutral, Satisfied, or Very Satis

mamaluj [8]

The results of the survey are shown in the table.

It's required to calculate the following probabilities:

a) A customer is neutral

The row labeled as 'Neutral' has a total of 79 customers out of 367 in total.

The required probability is:

$p=\frac{79}{367}$

b) A customer is a walk-in

The first column labeled as 'Walk-in' has a total of 106 customers out of 367. The required probability is

$p=\frac{106}{367}$

c) A customer is dissatisfied and a walk-in.

We have to cross the row Dissatisfied with the column Walk-in. The number of customers that have both categories is 22 out of 367.

The required probability is:

$p=\frac{22}{367}$

d) A customer is very satisfied given he saw a TV ad.

This is a conditional probability, where the total is 111 because is the given condition. The customers that have both characteristics are 33, thus the required probability is:

$p=\frac{33}{111}=\frac{11}{37}$

e) A customer is satisfied or referred.

Total satisfied = 139

Total referred = 150

With both features = 62

Total customers with one or both features: 139 + 150 - 62 = 227

We have to subtract the common feature because it was counted twice.

The required probability is:

$p=\frac{227}{367}$

6 0

1 year ago