Question

Determine the molarity of a solution formed by dissolving 468 mg of mgi2 in enough water to yield 50.0 ml of solution.

Answer 1

Answer : The molarity of a solution is, 0.0337 M

Explanation : Given,

Mass of $MgI_2$ = 468 mg  = 0.468 g   (1 mg = 0.001 g)

Volume of solution = 50.0 mL

Molar mass of $MgI_2$ = 278 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Mass of }MgI_2\times 1000}{\text{Molar mass of }MgI_2\times \text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{0.468g\times 1000}{278g/mole\times 50.0mL}=0.0337mole/L=0.0337M$

Therefore, the molarity of a solution is, 0.0337 M