I believe the correct factor concerning ionization energy within a period would be that the valence electrons essentially remain at about the same distance from the atomic nucleus when moving from left to right on the periodic table. This is because the Atomic number increases by a value of 1, and depending whether or not the maximum number of electrons are found within the shell, it may have another shell or not.
Balanced chemical reaction: C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(g).
<span>There are same number
of atoms of on both side of balanced chemical reaction: ten oxygen atoms, three carbon atoms and eight hydrogen atoms.
</span>Carbon is oxidized and oxygen is reduced in this balanced chemical reaction of combustion of propane.
Answer:
When zinc is added to copper sulphate (CUSO4) solution due to more reactivity of zinc, cooper is replaced by the zinc and forms zinc sulphate. During the process, the colour of the solution changes from blue to colourless.
It has a role as a fertilizer. It is a potassium salt and an inorganic chloride.
Answer:
The correct answer is 89.6 L
Explanation:
We have the following chemical equation and the molar masses for the reaction:
3H₂(g) + N₂ --> 2 NH₃
6 g 28 g 34 g
That means that 3 moles of H₂ (6 g) reacts with 1 mol of N₂ (28 g) and gives 2 moles of NH₃ (34 g). In order to calculate how many liters of NH₃ result from the reaction of 12 grams of H₂ and 28 grams of N₂, we have to first figure out which reactant is the <em>limiting reactant</em>. According to the equation, if 6 grams of H₂ reacts with 28 g of N₂, and we have 12 grams:
6 g H₂------- 28 g N₂
12 g H₂-------- X = 12 g H₂ x 28 g N₂/6 g H₂ = 56 g N₂
We need 56 g of N₂ but we have 28 g of N₂, so <em>N₂ is the limiting reactant</em>. With the limiting reactant we can calculate the moles of product (NH₃) we will obtain:
We have 28 g N₂ -----> 28 g/14 g/mol = 2 moles N₂
1 mol N₂ ----------- 2 moles NH₃
2 mol N₂ --------- X = 2 mol N₂ x 2 moles NH₃/1 mol N₂ = 4 mol NH₃
Finally, we convert the moles of NH₃ to liters:
1 mol gas at STP = 22.4 L
Liters NH₃ obtained = 4 moles NH₃ x 22.4 L/1 mol = 89.6 L