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Ierofanga [76]
2 years ago
12

A 0.73 m solution of chloroacetic acid, , has a ph of 1.50. calculate for the acid.

Chemistry
1 answer:
erik [133]2 years ago
6 0
PH = 0.1289<span> for </span>1.50<span> M solution of weak acid with Ka value of </span><span>.73</span>
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A fluorine atom has 9 positive charge,9 negative charges and a mass of 19. Describe the structure of its atom.
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The atomic structure of the atom contains 9 positively charged particles (protons) and 10 neutrally charged particles (neutrons) in the center of the atom in a clump called the nucleus. Those 9 negatively charged particles (electrons) are moving around outside of the nucleus.
There are 10 neutral charges, because the mass of 19 comes from the number of neutral charges plus the number of positive charges.
To calculate the number of neutral charges, subtract the positive charges from the mass (19 - 9), and you get the number of neutral charges (10).


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Which of the following groups of atoms are most likely to have similar properties?
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The third option because the elements mentioned in that selection are in the same group, they must have similar properties.
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If the Kelvin temperature of a gas is doubled, the volume of the gas will increase by ____
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If the Kelvin temperature of a gas is doubled, the volume of the gas will increase by two. It follows Charles law where in for a mixed gas of mass, the volume is directly proportional to the temperature at constant pressure.

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2 years ago
What is - 10°F in degrees Celsius
Anon25 [30]

Answer:

-23.333 °C

Explanation:

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3 years ago
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If 20.0 ml of glacial acetic acid (pure hc2h3o2) is diluted to 1.40 l with water, what is the ph of the resulting solution? the
Y_Kistochka [10]

By using the formula, mass = density x volume, we calculate mass in grams

 20.0 mL CH₃COOH x (1.05 g / mL) = 21.0 g CH₃COOH 

To find the moles, molar mass of CH₃COOH = 60.05g/mol<span>

21.0 g </span>CH₃COOH x (1 mole CH₃COOH / 60.05 g CH₃COOH) = 0.350 moles CH₃COOH 

To find molarity,<span>

[</span>CH₃COOH] = moles CH₃COOH / L of solution = 0.350 / 1.40 = 0.250 M CH₃COOH<span> 

When </span>CH₃COOH is dissolved in water, it produces small and equal amounts of H₃O⁺+ and C₂H₃O₂⁻. 

<span>
Molarity ,         </span>CH₃COOH<span> + H</span>₂O <==> H₃O⁺ + C₂H₃O₂⁻ 

<span> <span>Initial                      0.250                          0           0 </span>
Change                      -x                            x            x 
Equilibrium            0.250-x                        x            x 

K</span>ₐ = [H₃O⁺][C₂H₃O₂⁻] / [HC₂H₃O₂] = (x)(x) / (0.250-x) = 1.8 x 10⁻⁵

<span>Since K</span>ₐ is relatively small, we can neglect the -x term after 0.250 to simplify 

<span>x</span>² / 0.250 = 1.8 x 10⁻⁵ 

x² = 4.5 x 10⁻⁶ 

<span> x = 2.1 x 10</span>⁻³<span> = [H</span>₃O⁺] 

pH = -log [H₃O⁺] = -log (2.1 x 10⁻³) = 2.68

8 0
3 years ago
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