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elena55 [62]
3 years ago
11

When you squeeze an air-filled balloon, what happens inside?

Chemistry
1 answer:
Harman [31]3 years ago
4 0

Option D

When you squeeze an air-filled balloon, what happens inside: There are more collisions of air molecules against the wall of the balloon.

<u>Explanation:</u>

If you compress off the balloon, one seemingly sense the air forcing up on the wall of the balloon with indeed more imposing power. This rise in force is due to a drop in quantity. By squeezing the balloon, you lessen the area the gas bits can hold.

As the particles are driven a little closer collectively, they oppose more, so the force from the moving gas bits rises.  Boyle’s Law pronounces that the quantity of a determined quantity of gas limits as its load rises. If the quantity rises, its load reduces.

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Given that a for HCN is 6. 2×10^−10 at 25 °C. What is the value of b for cn− at 25 °C?
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If Ka for HCN is 6. 2×10^−10 at 25 °C, then the value of Kb for cn− at 25 °C is 1.6 × 10^(-5).

<h3>What is base dissociation constant? </h3><h3 />

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 6.2× 10^(-10)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{6.2×10^(-10) }

= 1.6× 10^(-5)

Thus, the value of base dissociation constant at 25°C is 1.6 × 10^(-5).

learn more about base dissociation constant :

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4 0
2 years ago
Please help. I need someone smart
Sveta_85 [38]
5678+910=13000
257-466=198
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Answer:

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