The heat required to vaporize 43.9 g of acetone at its boiling point is calculated as below
the heat of vaporization of acetone at its boiling point is 29.1 kj/mole
find the moles of acetone = mass/molar mass
= 43.9g /58 g/mol =0.757 moles
heat (Q) = moles x heat of vaporization
= 29.1 kj/mole x 0.757 moles = 22.03 kj
Answer:


Explanation:
1 mol of nitrogen at STP = 22.4 L = 22400 cc
n = Mol of
= 
M = Molar mass of
= 
= Avogadro's number = 
Mass of
is

Mass of the nitrogen is 
Number of molecules is given by

The number of molecules present in it are 
An element is a form of matter that is made of only one type of atom
Using the law of dilution :
Mi x Vi = Mf x Vf
2.00 x Vi = 0.15 x 100.0
2.00 x Vi = 15
Vi = 15 / 2.00
Vi = 7.5 mL
hope this helps!