Answer : The mass of the water in two significant figures is, ![3.0\times 10^1g](https://tex.z-dn.net/?f=3.0%5Ctimes%2010%5E1g)
Explanation :
In this case the heat given by the hot body is equal to the heat taken by the cold body.
![q_1=-q_2](https://tex.z-dn.net/?f=q_1%3D-q_2)
![m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_f-T_1%29%3D-m_2%5Ctimes%20c_2%5Ctimes%20%28T_f-T_2%29)
where,
= specific heat of iron metal = ![0.45J/g^oC](https://tex.z-dn.net/?f=0.45J%2Fg%5EoC)
= specific heat of water = ![4.18J/g^oC](https://tex.z-dn.net/?f=4.18J%2Fg%5EoC)
= mass of iron metal = 32.3 g
= mass of water = ?
= final temperature of mixture = ![59.2^oC](https://tex.z-dn.net/?f=59.2%5EoC)
= initial temperature of iron metal = ![21.9^oC](https://tex.z-dn.net/?f=21.9%5EoC)
= initial temperature of water = ![63.5^oC](https://tex.z-dn.net/?f=63.5%5EoC)
Now put all the given values in the above formula, we get
![32.3g\times 0.45J/g^oC\times (59.2-21.9)^oC=-m_2\times 4.18J/g^oC\times (59.2-63.5)^oC](https://tex.z-dn.net/?f=32.3g%5Ctimes%200.45J%2Fg%5EoC%5Ctimes%20%2859.2-21.9%29%5EoC%3D-m_2%5Ctimes%204.18J%2Fg%5EoC%5Ctimes%20%2859.2-63.5%29%5EoC)
![m_2=30.16g\approx 3.0\times 10^1g](https://tex.z-dn.net/?f=m_2%3D30.16g%5Capprox%203.0%5Ctimes%2010%5E1g)
Therefore, the mass of the water in two significant figures is, ![3.0\times 10^1g](https://tex.z-dn.net/?f=3.0%5Ctimes%2010%5E1g)
Answer:
mercury( specific heat=0.140j/gc)
Answer:
The amount of work done on the system is 18234 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.
Explanation:
Thermodynamic work is called the transfer of energy between the system and the environment by methods that do not depend on the difference in temperatures between the two. When a system is compressed or expanded, a thermodynamic work is produced which is called pressure-volume work (p - v).
The pressure-volume work done by a system that compresses or expands at constant pressure is given by the expression:
W system= -p*∆V
Where:
- W system: Work exchanged by the system with the environment. Its unit of measure in the International System is the joule (J)
- p: Pressure. Its unit of measurement in the International System is the pascal (Pa)
- ∆V: Volume variation (∆V = Vf - Vi). Its unit of measurement in the International System is cubic meter (m³)
In this case:
- p= 10 atm= 1.013*10⁶ Pa (being 1 atm= 101325 Pa)
- ΔV= 2 L- 20 L= -18 L= -0.018 m³ (being 1 L=0.001 m³)
Replacing:
W system= -1.013*10⁶ Pa* (-0.018 m³)
Solving:
W system= 18234 J
<u><em>The amount of work done on the system is 18234 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.</em></u>
<span>The answer to the question is the option C. it cannot be physically broken down into different types of atoms. This means that the material is an element, which is a pure substance. Because an element is a pure substance that is formed by one only type of atoms. For example, gold is an element and all its atoms are of the same type. That is also true for any of the 118 elements of the periodic table. Compounds (other kind of pure substances) can be broken down into molecules (which contain different kind of atoms, but always in the same proportion) and mixtures (non pure substances) have different kind of substances.</span>